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Ber [7]
2 years ago
8

A right cylindrical solid is cut in half to form the figure shown. If the length is 20 cm and the diameter is 8 cm, what is the

surface area?
A. (80π + 160) cm2
B. (96π + 160) cm2
C. 320π cm2
D. (320π + 160) cm2
(This question is on ed)
Mathematics
2 answers:
I am Lyosha [343]2 years ago
6 0

Answer:

The answer is B. (96π + 160) cm2

Step-by-step explanation:

Just took the assignment on edge.

kogti [31]2 years ago
4 0
The answer for this question is C
You might be interested in
HELP!!!!
Nonamiya [84]
Your answer is E. $25.

First let under 12 = u, over 12 = o, and adults = a.
We can now write the equations:

2u + 3a + 3o = 174
4u + 2a = 122
a + o = 46

Because we know that a + o = 46, and 3a + 3o is in the first equation, we can multiply 46 by 3 to get what 3a + 3o equals. This makes 138.
Now we can substitute 138 into the first equation to get 2u + 138 = 174
2u = 36
u = 18

Now that we know what u equals, we can substitute it in to the second equation to get:
4(18) + 2a = 122
72 + 2a = 122
2a = 50
a = $25

I hope this helps! Let me know if you have any questions :)
8 0
3 years ago
The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

AV = \frac{y(t2) - y(t1)}{t2 - t1}

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii)  t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8

So the average speed is -128.9 ft/s

iii)  t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0
3 years ago
The sum of two numbers is 54. The large number is 18 more than the sampler number. What are the numbers ?
Karolina [17]

Answer: a=36; b=18


Step-by-step explanation:

1. You know that the sum of two numbers is 54, then, you have:

a+b=54

2. According to the problem, the larger number is 18 more than the sampler number, this can be expressed as following:

a=b+18

3. Then, you must substitute the second equation into the first equation and solve for b:

b+18+b=54

b=18

4. Then the value of a is:

a+18=55

a=36



7 0
3 years ago
I will give 50 points
ikadub [295]

Answer:

f(x) = x³+2x²-16x-32

Step-by-step explanation:

f(x) = 0 when x = -4, -2, 4

So these are the roots

Factors are (x+4)(x+2)(x-4)

f(x) = [(x+4)(x-4)](x+2)

f(x) = (x²-16)(x+2)

f(x) = x³+2x²-16x-32

8 0
2 years ago
Read 2 more answers
The height of a triangle is 4 sqrt 3 . What is the perimeter of the equatorial triangle?
Karo-lina-s [1.5K]

The perimeter of the equatorial triangle is 24 units

<h3><u>Solution:</u></h3>

Given that,

An equilateral triangle has an height equal to 4 \sqrt{3}

The triangle is shown below

From Triangle ABC in the shown figure AD =4 \sqrt{3}

Let the sides of the equilateral triangle be ‘a’

AB = BC = a

Since, it is an equilateral triangle we get,

BD = DC = a ÷ 2

Now, using Pythagoras Theorem in Triangle ABD,

The Pythagorean theorem is this: In a right triangle, the sum of the squares of the lengths of the two legs is equal to the square of the length of the hypotenuse.

\mathrm{AB}^{2}=\mathrm{BD}^{2}+\mathrm{AD}^{2}

\begin{array}{l}{a^{2}=\left(\frac{a}{2}\right)^{2}+(4 \sqrt{3})^{2}} \\\\ {a^{2}-\left(\frac{a}{2}\right)^{2}=(4 \sqrt{3})^{2}}\end{array}

\frac{4 a^{2}-a^{2}}{4}=16 \times 3

\begin{array}{l}{\frac{3 a^{2}}{4}=16 \times 3} \\\\ {3 a^{2}=192} \\\\ {a^{2}=192 \div 3=64}\end{array}

a = 8

Hence, the three sides of the triangle are 8 units each

In equilateral traingle, length of all three sides of triangle are equal

So, Perimeter = 3 \times (Length of each side of triangle)

Perimeter = 3 \times 8 = 24

Thus the perimeter of the equatorial triangle is 24 units

7 0
3 years ago
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