The additive inverse of -4b is 4b
Answer:
-6s-c+1
Step-by-step explanation:
(-3s-4c+1)+(-3s+3c)
We have been given the above expression. To find the sum, we simply collect the like terms and combine them;
(-3s-4c+1)+(-3s+3c) = -3s + -3s -4c + 3c + 1
-3s + -3s -4c + 3c + 1 = -3s - 3s + 3c - 4c + 1
-3s - 3s + 3c - 4c + 1 = -6s - c + 1
Therefore;
(-3s-4c+1)+(-3s+3c) = -6s-c+1
Answer:
D
Step-by-step explanation:
TS and QR Is your answer
Answer:
3
Step-by-step explanation:
The value of "a" is the coefficient of x^2, so we know that is 2.
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<u>Solve for h</u>
Now, we have ...
2x^2 -8x +7 = 2(x -h)^2 +k
Expanding the right side gives us ...
= 2(x^2 -2hx +h^2) +k
= 2x^2 -4hx +2h^2 +k
Comparing x-terms, we see ...
-4hx = -8x
h = (-8x)/(-4x) = 2
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<u>Solve for k</u>
Now, we're left with ...
2h^2 +k = 7 = 2(2^2) +k = 8 +k
Subtracting 8 we find k to be ...
k = 7 -8 = -1
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And the sum of constants a, h, and k is ...
a +h +k = 2 +2 -1 = 3
The sum of the constants is 3.
Answer:
Step-by-step explanation:
