False.
Right triangles do not have to be congruent.
:)
9514 1404 393
Answer:
15
Step-by-step explanation:
In vector form, the equation of point p on the line can be written as ...
p = (-3, -4) +t(25 -(-3), 38 -(-4)) . . . . . for some scalar t
p = (-3, -4) +t(28, 42)
p = (-3, -4) +14t(2, 3)
where t takes on any value between 0 and 1.
If we let t = n/14 for some integer 0 ≤ n ≤ 14, then the coordinates of point p will be integers.
There are 15 values that n can have in the allowed range.
The caterpillar touches 15 points with integer coordinates.
I need a picture of the figures to help with this!
Answer:
B- Parallelogram PQRS is also a rhombus.
Step-by-step explanation:
Given
Parallelogram PQRS with perpendicular diagonals
Required
Which of the option is true
(a) PQRS can be a rectangle
A rectangle do not have perpendicular diagonals.
Hence, (a) is false
<em>If (a) is false, then (d) is also false</em>
(b) PQRS can a rhombus
The diagonals of a rhombus are not perpendicular.
So (b) <em>is true</em>
<em>No need to check for (c), since only option is true</em>
Let f be the height of the fir trees
Let p be the height of the pine trees
We know from the problem that
f + p = 21 and 4f = 24 + p
rearrange the 2nd equation to get p = 4f - 24 and substitute into the other equation
so...
f + 4f - 24 = 21
5f - 24 = 21
5f = 45
f = 9 - height of the fir tree
substitute back into the 1st equation
9 + p = 21
p = 12 - height of the pine tree
