C = 3.5t....when t = 15
c = 3.5(15)
c = 52.50 <==
We can solve this problem by referring to the standard
probability distribution tables for z.
We are required to find for the number of samples given the
proportion (P = 5% = 0.05) and confidence level of 95%. This would give a value
of z equivalent to:
z = 1.96
Since the problem states that it should be within the true
proportion then p = 0.5
Now we can find for the sample size using the formula:
n = (z^2) p q /E^2
where,
<span> p = 0.5</span>
q = 1 – p = 0.5
E = estimate of 5% = 0.05
Substituting:
n = (1.96^2) 0.5 * 0.5 / 0.05^2
n = 384.16
<span>Around 385students are required.</span>
Answer:
So the answer is v=112 sa=165
Step-by-step explanation:
Try using formulas such as 1
4h﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4
and
A=12bh
Answer:
bbc
bbc
ssc
Step-by-step explanation:
hahah
Answer:
13
Step-by-step explanation:
