All categories

3 years ago

-7d>105 what is the solution?

Mathematics

2 answers:

Bumek [7]3 years ago

4 0

Answer: d < -15

Explanation: When you're asked to solve an inequality like -7d < 105, your goal should be the same as it was when solving equations, to get <em>d</em> by itself on one side.

In this problem since <em>d</em> is being multiplied by -7 on the left side of the inequality, to get <em>d</em> by itself, we divide both sides by -7. But here is the rule you have to watch out for when solving inequalities.

When you divide both sides of an inequality by a negative number, you must switch the direction of the inequality sign.

So this greater than in our original problem becomes less than in our second step. On the left side, the -7's cancel and we are left with <em>d</em> and on the right side, 105 divided is -15. So we have <em>d < -15</em>.

Notice that I switched the direction of the inequality sign above.

Jet001 [13]3 years ago

3 0

Answer:

d <-15

In interval notation

(-∞,-15)

Step-by-step explanation:

-7d>105

Divide each side by -7. remembering to flip the inequality

-7d/-7 < 105/-7

d <-15

You might be interested in

An online music club sells compact discs for $13.95 each plus $1.95 shopping and handling per order. If Maria’s total bill was $

Korvikt [17]

$85.65 = 13.95x + 1.95$
$83.7 = 13.95x$
$6 = x$
6 CDs

3 0

3 years ago

Solve this polynomial:

irina [24]

Answer:

-4r²-3s²

Step-by-step explanation:

Remove unnecessary parentheses:

r²+s²-(5r²+4s²)

Connect like terms:

-4r²+s²-4s²

Simplify/ collect like terms:

-4r²-3s²

Solution:

-4r²-3s²

6 0

3 years ago

Read 2 more answers

Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer. How many imaginary r

Rainbow [258]

Answer:

<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>

Step-by-step explanation:

Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:

<h3>To find how many imaginary roots does the polynomial have :</h3>

Since the degree of given polynomial is 4
Therefore it must have four roots.
Already given that the given polynomial has 1 positive real root and 1 negative real root .
Every polynomial with degree greater than 1 has atleast one imaginary root.

<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>

8 0

3 years ago

How to do RX - sx + y equals B plzz explain how to get the answer there all variables!!!!

zalisa [80]

Rx - sx + y = b

WHEN SOLVING FOR X :

rx - sx + y = b

We must get x onto it's own side, so subtract y from both side.s

rx - sx = b - y

Then, factor out x.

x(r - s) = b - y

Then, divide both sides by (r - s).

x(r - s) ÷ (r - s) = b - y ÷ (r - s)

Simplify.

x = b - y / r - s → $x = \frac{b-y}{r-s}$

WHEN SOLVING FOR Y :

rx - sx + y = b

We need to isolate y, so get rid of everything BUT y on the left side.

Subtract rx from both sides.

-sx + y = b - rx

Then, add sx to both sides.

y = b - rx + sx

~Hope I helped!~

5 0

3 years ago

Solve the quotient of 9.36 and 0.3

Anestetic [448]

31.2

steps:
9.36/3 = 31.2

quotient is the solution to division

4 0

3 years ago

Read 2 more answers