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gogolik [260]
3 years ago
7

Please help, need an answer ASAP!

Mathematics
1 answer:
andrey2020 [161]3 years ago
8 0

i can't see the picture

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Demonstrate two different ways to solve the equation 5^(2x+1) = 25.
Tanzania [10]

Answer:

Step-by-step explanation:

Method 1: Taking the log of both sides...

So take the log of both sides...

5^(2x + 1) = 25

log 5^(2x + 1) = log 25 <-- use property: log (a^x) = x log a...

(2x + 1)log 5 = log 25 <-- distribute log 5 inside the brackets...

(2x)log 5 + log 5 = log 25 <-- subtract log 5 both sides of the equation...

(2x)log 5 + log 5 - log 5 = log 25 - log 5

(2x)log 5 = log (25/5) <-- use property: log a - log b = log (a/b)

(2x)log 5 = log 5 <-- divide both sides by log 5

(2x)log 5 / log 5 = log 5 / log 5 <--- this equals 1..

2x = 1

x=1/2

Method 2

5^(2x+1)=5^2

2x+1=2

2x=1

x=1/2

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3 years ago
I need help with the following if possible
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What is 6 and 2/5 + 7 and 9/10? simplify answer
netineya [11]

Answer:

Step-by-step explanation:

What I would do is convert everything to have a denominator of 10 so it could be easier to add.

6 would equal 60/10

7 would equal 70/10

2/5 would equal 4/10

now add all together

60/10 + 70/10 + 4/10 +9/10 and you get 143/10. If you wanted to simplify you would get 14 3/10 or 14.30

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