Answer: (3x + 11y)^2
Demonstration:
The polynomial is a perfect square trinomial, because:
1) √ [9x^2] = 3x
2) √121y^2] = 11y
3) 66xy = 2 *(3x)(11y)
Then it is factored as a square binomial, being the factored expression:
[ 3x + 11y]^2
Now you can verify working backwar, i.e expanding the parenthesis.
Remember that the expansion of a square binomial is:
- square of the first term => (3x)^2 = 9x^2
- double product of first term times second term =>2 (3x)(11y) = 66xy
- square of the second term => (11y)^2 = 121y^2
=> [3x + 11y]^2 = 9x^2 + 66xy + 121y^2, which is the original polynomial.
Answer:
4x+12
Step-by-step explanation:
Answer:
hope it helps...
Step-by-step explanation:
Whenever the equation of a line is written in the form y = mx + b, it is called the slope-intercept form of the equation. The m is the slope of the line. And b is the b in the point that is the y-intercept (0, b). For example, for the equation y = 3x – 7, the slope is 3, and the y-intercept is (0, −7).
Answer:
1) 5
2) 5
Step-by-step explanation:
Data provided in the question:
(3²⁷)(5¹⁰)(z) = (5⁸)(9¹⁴)(
)
Now,
on simplifying the above equation
⇒ (3²⁷)(5¹⁰)(z) = (5⁸)((3²)¹⁴)()
or
⇒ (3²⁷)(5¹⁰)(z) = (5⁸)(3²⁸)()
or
⇒ 
or
⇒
or
⇒
we can say
x = 5, y = 2 and, z = 3
Now,
(1) y is prime
since, 2 is a prime number,
we can have
x = 5
2) x is prime
since 5 is also a prime number
therefore,
x = 5
