What is the sum of square root -2 and square root -18

Mathematics

1 answer:

GarryVolchara [31]4 years ago

5 0

answer:

4 square root of 2 i (i it's outside the square root)

explanation:

square root of -2 = square root of 2 i (i being outside)

and square root of -18 = square root of 1 and square root of 9*2, square root of 1 = i, and the square root of 9 is 3, leaving square 2 alone

so it would look like:

square root of 2 i PLUS 3 square root of 2 i (i being outside as well)

there is a 1 outside the square root of 2 i, that 1 adds up with the 3 and since the square roots are the same, they stay the same

so 4 square root of 2 i

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Answer:

a. Maximum= 27, minimum= -5

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Step-by-step explanation:

We have the function $f(x)=8x-5$ . Since the function correspond to a line, then the maximum and minimum values of the function over an interval are in the endpoints of the interval.

Observe that if the line has negative slope then the minimum value is in the right endpoint. If the line has positive slope the minimum value is in the left endpoint of the interval.

The function f(x) has slope m=8. Then

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b. the minimum value of f(x) in the interval [-4,,3] is reach when x=-4, and the minimum is $f(-4)=8(-4)-5=-32-5=-37$ and the maximum is $f(3)=8(3)-5=24-5=19$