Match each equation to its factorized version and solution.
1 answer:
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Answer: Choice D
b greater-than 3 and StartFraction 2 over 15 EndFraction
In other words,
b > 3 & 2/15
or
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Explanation:
Let's convert the mixed number 2 & 3/5 into an improper fraction.
We'll use the rule
a & b/c = (a*c + b)/c
In this case, a = 2, b = 3, c = 5
So,
a & b/c = (a*c + b)/c
2 & 3/5 = (2*5 + 3)/5
2 & 3/5 = (10 + 3)/5
2 & 3/5 = 13/5
The inequality is the same as
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Let's multiply both sides by 15 to clear out the fractions
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Now isolate the variable b
Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how
47/15 = 3 remainder 2
The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.
Answer:
1a) Length = 7x + 3 & Width = 4x - 2
1b) Area =
1c) Area = 2774 sq. m
2.
Step-by-step explanation:
1a)
The length given as words is "3 more than 7 times x"
The width given as words is "4 times x minus 2"
The expression for length would be 7x + 3
The expression for width would be 4x - 2
1b)
The area is length * width
Since we already know the algebraic expressions for length and width from part (a) above, we use the formula:
Area = (7x+3)(4x-2) = 28x^2 -14x + 12x - 6 = 28x^2 -2x -6
Area =
1c)
Given x = 10, we put this into the area expression we found in (b) above.Let's see:
Area = 2774 sq. m
2.
We can group the first two terms and next two terms and write up:
That's the factored form.