Answer:
Step-by-step explanation:
The Weight of Ingredients to be used by Chef Selena are:
pounds of pasta, - 6 pounds of sauce; and
pounds of onions.
Total Weight of Food Made, x
Since each serving is 
Number of Servings of her dish, y
The two equations needed to solve the problem are therefore:
Answer:
0.0625
Step-by-step explanation:
The prevalence of gene a = 25 %, P (a) = 0.25
birth defect occurs when both parents have prevalence of gene a.
P (Defect) = P ( Both parents have gene a)
If both parents inherit the gene a independently, the the individual will have a birth defect when both parents have gene a.
P ( Father having gene a) = 0.25
P ( Mother having gene a) = 0.25
Hence,
P (Birth Defect) = P ( Both parents have gene a) = 0.25 * 0.25 = 0.0625
The equation of a line is written as y =Mx + b, where m is the slope and b is the y intercept, which is the y value when x = 0.
You are told the slope is -1/4, so replace m with -1/4. You are also given the point (0,0) which means when x is 0, y is also 0, so replace b with 0.
The equation becomes y= -1/4x + 0
Because y is 0 you aren’t adding anything to the equation so you can remove it from the equation.
Answer is y = -1/4x
Answer:
are you a teacher
Step-by-step explanation:
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 17
For the alternative hypothesis,
µ < 17
This is a left tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 80,
Degrees of freedom, df = n - 1 = 80 - 1 = 79
t = (x - µ)/(s/√n)
Where
x = sample mean = 15.6
µ = population mean = 17
s = samples standard deviation = 4.5
t = (15.6 - 17)/(4.5/√80) = - 2.78
We would determine the p value using the t test calculator. It becomes
p = 0.0034
Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.
The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.
