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Lesechka [4]
4 years ago
11

Which expressions simplify to 0? Check all that apply. 8g – 8g, (–2g) – 2g, 5g + (–5g), One-half g + one-half, g Negative two-th

irds g + two-thirds g
Mathematics
2 answers:
victus00 [196]4 years ago
6 0

We have been given 4 expressions. We are asked to choose the expressions, which simplifies to 0.

Let us check our given choices one by one.

1. 8g-8g

8(g-g)

8(0)=0

When we will subtract 8g from 8g, we will get 0. Therefore, expression 8g-8g simplifies to 0.

2. (-2g)-2g

Let us remove parenthesis.

-2g-2g

Upon combining like terms, we will get:

-4g

Since  (-2g)-2g simplifies to -4g, therefore, expression -2g-2g is not a correct choice.

3. 5g+(-5g)

Let us remove parenthesis.

5g-5g

Upon combining terms, we will get:

5g-5g=0

Since  5g+(-5g) simplifies to 0, therefore, expression  5g+(-5g) is a correct choice.

4. \frac{1}{2}g+\frac{1}{2}g-\frac{2}{3}g+\frac{2}{3}g

Let us combine the terms as:

\frac{1+1}{2}g-\frac{2}{3}g+\frac{2}{3}g

\frac{2}{2}g-\frac{2}{3}g+\frac{2}{3}g

g-g(-\frac{2}{3}+\frac{2}{3})

g-g(0)

g-(0)=g

Since \frac{1}{2}g+\frac{1}{2}g-\frac{2}{3}g+\frac{2}{3}g simplifies to g, therefore, expression \frac{1}{2}g+\frac{1}{2}g-\frac{2}{3}g+\frac{2}{3}g is not a correct choice.

Setler [38]4 years ago
6 0

Answer:

its 1,3,5

1Step-by-step explanation:

trust me

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Answer:

No, it is not.

Step-by-step explanation:

This is because if you look at the expression, there is no term that is raised to the cube root. As a result, this isn't a cubic polynomial. However, this would be a quadratic polynomial cause the highest raised exponent is 2, which is the number for quadratic.

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3 years ago
The perimeter of a rectangle is 16.6km, and its area is 13.42km2. Find its length and width. length : km width : km
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Answer:

l=5.12 & w=2.62

Step by step explanation:

A=l×w

13.42=lw

w=13.42/l

p = 2(l + w) \\ 16.6 = 2(l +  \frac{13.42}{l} ) \\ 16.6 = 2( \frac{ {l}^{2}  + 13.42}{l}) \\ 16.6 = 2(l + 13.42) \\ 16.6 = 2l + 26.84 \\ 2l = 26.84 - 16.6 \\ 2l = 10.24 \\ l =  \frac{10.24}{2}  \\ l = 5.12km

Since you have found the value of the length you can find the value.of the width.

w =  \frac{13.42}{l}  \\ w =  \frac{13.42}{5.12}  \\ w = 2.62km

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