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3 years ago

Which ordered pair is a solution to the system of linear equations -4x+y=8 and x-5y=17

Mathematics

1 answer:

photoshop1234 [79]3 years ago

8 0

Answer: -3

Step-by-step explanation:

You might be interested in

Simplify a•a²•a³ of the following

professor190 [17]

Answer:

a^6

Step-by-step explanation:

when multiplying exponents, add the exponents together. you can distribute to prove it, a^2 is a•a, a^3 is a•a•a so by bringing it together you get a•(a•a)•(a•a•a) which gets a 6 times or a^6

5 0

4 years ago

Miguel made 80 on his Math test. He made 95 in last week's Math test. What is the percent of change on his scores? (Round your

storchak [24]

Answer:

15.78 %

Step-by-step explanation:

It is given that,

Miguel made 80 on his Math test. He made 95 in last week's Math test.

We need to find the percent change on his scores. It can be calculated as follows :

$\%=\dfrac{\text{original score-initial score}}{\text{original socre}}}\times 100\\\\\%=\dfrac{95-80}{95}\times 100\\\\\%=15.78\%$

So, there is a percent change of 15.78%.

4 0

3 years ago

WILL GIVE BRAINLIEST!

Vsevolod [243]

Step-by-step explanation:

the answer to your question with roster method is

(-5,-4,-3,-2 and -1)

8 0

3 years ago

In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that

attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable $X\sim Poisson(\lambda = 0.62)$ .

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

= 1 - P (X = 0) - P (X = 1)

$=1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252$

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: $\lambda=7\times0.62=4.34$

Compute the probability of no deaths in a corps over 7 years as follows:

$P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130$

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0

3 years ago

Two young sumo wrestlers decided to go on a special diet to gain weight rapidly. They each gained weight at a constant rate. The

Radda [10]

Answer: the first wrestler gains more at the beginning, the second wrestler gains more faster

Step-by-step explanation:

5 0

3 years ago