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serg [7]
3 years ago
7

To boost holiday sales, a jewelry store in Bismarck, North Dakota, is advertising the following promotion: "If more than seven i

nches of cumulative snow fall on December 24, 25, 26, 27, and 28, you get your money back on all purchases made on December 17." To analyze this promotion, the store manager has collected data and determined that snowfall over this 5-day period in December is normally distributed with an average of 6 inches and standard deviation of 0.559 inches. What is the probability that the store will have to refund the money to its December 17 customers? If required, round your answer to three decimal places.

Mathematics
1 answer:
REY [17]3 years ago
6 0

Answer:

  about 0.037

Step-by-step explanation:

A suitable probability calculator can provide the probability that 7 inches will be exceeded. It is about 0.036815.

The probability the store will have to refund money is about 0.037.

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Fran’s store spent $64,000 on expenses last year. Rent of the store was 35% of those expenses .How much did Fran spend on rent.
andrezito [222]

Answer:

$22400

Step-by-step explanation:

multiply 64000 with 0.35 (35%)

6 0
2 years ago
What are two fractions equivalent to 5/12
saul85 [17]

Answer:

10/24 and 15/36, more answers possible

Step-by-step explanation:

if you multiply both the numerator and denominator by the same number, it will always be equivalent to 5/12, as you can simplify it back to that fraction.

5/12, multiply both by two, and you have 10/24

5/12, multiply both by three, and you have 15/36

5 0
3 years ago
3(x - 5) = 2 (x - 5 + x is it true or false
katovenus [111]

Answer:

Step-by-step explanation:

3x3=9-5=4 false

______________

2x2=4-5= -0+5x5=25false

6 0
2 years ago
Read 2 more answers
sons in the NHL,nts than anyone whoccomplished thiser games thanHer. Here are theRg each season:74, 45, 81, 48, 80,Working for a
vesna_86 [32]

Step 1:

In descriptive statistics, a box plot or boxplot (also known as box and whisker plot) is a type of chart often used in explanatory data analysis. Box plots visually show the distribution of numerical data and skewness through displaying the data quartiles (or percentiles) and averages.

Step 2:

To sketch a boxplot, you will need to determine the following:

Minimum

Lower quartile

Median

Upper quartile

Maximum

Step 3:

USA

First arrange the data from the least to the greatest.

14 , 26, 33, 34, 35, 38, 40, 41, 44, 46, 46, 49, 53, 66, 70.

Minimum = 14

\begin{gathered} \text{Lower quartile position = }\frac{1}{4}(n+1)^{th} \\ \text{= }\frac{15+1}{4}\text{ = }\frac{16}{4}=4^{th} \\ Q_1\text{ = lower quartile = 34} \end{gathered}

Median = 41

\begin{gathered} \text{Upper quartile position = }\frac{3}{4}(n+1)^{th} \\ =\text{ }\frac{3\text{ }\times(15+1)}{4} \\ =12^{th} \\ Q_3\text{ = upper quartile  = 49} \end{gathered}

Maximum = 70

Interquartile range IQR = 49 - 34 = 15

Canada

22, 28, 31, 31, 35, 35, 36, 39, 40, 40, 42, 49, 53, 63, 68

Minimum = 22

\begin{gathered} Q1\text{  Position = }\frac{(n+1)^{th}\text{ }}{4}\text{ = }\frac{16}{4}th=4^{th} \\ Q_1\text{ = 31} \end{gathered}

Median = 39

\begin{gathered} UpperquartileQ_{_3\text{ }}\text{ = 49} \\  \end{gathered}

Maximum = 68

Interquartile range = 49 - 31 = 18

8 0
1 year ago
Find the value of X in the following figures​
Yanka [14]

Answer:

Scanner sc = new Scanner(System.in);

System.out.println(" ");

int n=sc.nextInt();

if(n==1)

System.out.println("January");

if(n==2)

System.out.println("Februry");

if(n==3)

System.out.println("March");

if(n==4)

System.out.println("April");

if(n==5)

System.out.println("May");

if(n==6)

System.out.println("june");

if(n==7)

System.out.println("July");

if(n==8)

System.out.println("August");

if(n==9)

System.out.println("September");

if(n==10)

System.out.println("October");

if(n==11)

System.out.println("November");

if(n==12)

System.out.println("December");

if(n==34)

System.out.println(" );

if(n==145)

System.out.println("to kaise hain aap log");

}

}

3 0
2 years ago
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