Question

The sides of a triangle are 56 CM, 60 cm and 52 cm find its area using herons formula ​

Answer 1

Answer:

1344cm^2

Step-by-step explanation:

Semi perimeter:

S = (a+b+c)/2

S=(56+60+52)/2

S=168/2

S=84

Area:

A=root S(S-56)(S-60)(S-52)

A=root 84(84-56)(84-60)(84-52)

A=root 84(28*24*32)

A=root 84(21504)

A=root1806336

A=1344cm^2

Answer 2

Answer:

Step-by-step explanation:

$s=\frac{a+b+c}{2}=\frac{56+60+52}{2}=\frac{168}{2}=84 cm\\\\s-a=84-56=28 cm\\s-b=84-60=24 cm\\\\s-c=84-52=32 cm\\\\Area=\sqrt{s*(s-a)(s-b)(s-c)} \\\\=\sqrt{84*28*24*32}=\sqrt{7*12*7*4*12*2*4*2*2*2}\\\\=7*12*4*2*2=1344 sq.cm$