3 years ago

Under which condition will two lines not have a common solution

1 answer:

7 0

Answer:

Each shows two lines that make up a system of equations. If the graphs of the equations intersect, then there is one solution that is true for both equations. If the graphs of the equations do not intersect (for example, if they are parallel), then there are no solutions that are true for both equations.

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Step-by-step explanation:

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Find the standard form of the circle x2 + y2 – 6x + 10y + 24 = 0 by completing the square.

hichkok12 [17]

Answer:

$(x-3)^2+ (y+5)^2=10$

Step-by-step explanation:

Given the equation of the circle: $x^2 + y^2 - 6x + 10y + 24 = 0$

We wish to express it in a Standard form:

We begin by re-arranging:

$x^2 - 6x + y^2 + 10y = - 24$

Next, divide the coefficient of x by 2, square it and add it to both sides.

Do the same for y.

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$(x-3)^2+ (y+5)^2 = - 24+9+25\\(x-3)^2+ (y+5)^2=10$

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3 years ago

Carlos is analyzing the results of an experiment on two groups of mice in which he compared the difference in their weight gain

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Given:difference in the mean weight gain is 0.60 gramsstandard deviation of the difference in sample mean is 0.305
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Step-by-step explanation:

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1.20 could be a possibility...

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