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kotegsom [21]
3 years ago
6

Factorise this expression as fully as possible 2x2 + 6x

Mathematics
1 answer:
butalik [34]3 years ago
6 0

Answer:

The factored expression is: 2x(x + 3)

Step-by-step explanation:

We are given the following expression:

2x^2 + 6x

To factorize it as fully as possible, we first find the GCF between the numeric values, and the coefficients:

Numeric:

GCF between 2 and 6 is 2, because:

2 - 6| 2

1 - 3|

1 and 3 are not divisible by the same number, so 2.

Coefficient:

Between x² and x, x.

Factorizing:

Simplifying by 2x.

2x(\frac{2x^2}{2x}+\frac{6x}{2x}) = 2x(x + 3)

The factored expression is: 2x(x + 3)

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Answer:

She messed up the equation, A= B x h, she changed it midway, and also, you need to add the one half to make the equation valid

Step-by-step explanation:

A=1/2 x b xh

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Four players scored all of the points for their team in a basketball game. Player A scored 35 of the points, Player B scored 8%,
rusak2 [61]
Player C scored 0.15 = 15% of the total.
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What is the area of the figure below
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135in.^2

Step-by-step explanation:

split into 2 shapes :

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2 years ago
The measure of ∠DAB equals 105º. The measure of ∠ACB equals 35º.<br><br><br>What is m∠ABC?
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1) We know that <DAB and <BAC are supplementary angles according to the exterior angle theorem, so we set up the following equation and solve:

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Three classes have the same number of students. The teachers compared attendance on one Friday. Mr. Lopez had 92.5% of his stude
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♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Suppose the number of students in one of the classes is :

x

So ;

Mr.Lopez \:   \: had \:  \:  \frac{92.5}{100}x \\

_________________________________

Mrs.Foster \:  \: had \:  \:  \frac{19}{20} x \\

So :

Mrs.Foster \:  \: had \:  \:  \frac{19 \times 5}{20 \times 5} x \\

Mrs.Foster \:  \: had \:  \:  \frac{95}{100}x \\

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Ms.Kelly \:  \: had \:  \: 0.9x

Ms.Kelly \:  \: had \:  \:  \frac{9}{10} x \\

Ms.Kelly \:  \: had \:  \:  \frac{90}{100} x \\

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Compare :

\frac{95}{100} x >  \frac{92.5}{100} x >  \frac{90}{100} x \\

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