Answer:
The equation ls: y = -4x - 16
Step-by-step explanation:
Given the point (-6, 8)
Given the line y = .25x - 7
Use a fraction:
y = 1/4x - 7
The slope is 1/4 (or .25)
The slope of a perpendicular line is the negative inverse or -4.
Use the point slope form and substitute:
y - y1 = m(x - x1)
y - 8 = -4(x - (-6))
y - 8 = -4x - 24
y = -4x - 16
Proof:
f(-6) = -4(-6) - 16
= 24 - 16
= 8, giving (-6, 8)
1 - For this one I am not too sure as I generally only work with values that require an unknown. This one is an unknown asking for the values to see the fraction equivalent to 3/4 however if I had to guess here it would probably be 9/12 as it asks what is equal to 3/4. 3 goes into 9 3 times and into 12 4 times so it equals 3/4. Note: 9/12 has a numerator less than the denom but so does 6/8 which is the lesser fraction and still equals 3/4.
2 - Well simply put.
3 - For this one we have to do a bit of work.
Basically just make an equation such as n for numerator and d for denominator.
d = 2n - 4
Now all we have to do is plug in.
2 * 3 - 4 = 2
<span>2 * 6 - 4 = 8 </span>
<span>2 * 9 - 4 = 14 </span>
<span>2 * 12 - 4 = 20
</span>So now we know our numerator or n equals 12.
The denominator or d equals 20 so we would get the fraction of....
Answer and Explanation:
Using trig ratios, we can express the given values of sin u and tan v as shown below
![\begin{gathered} \sin u=\frac{opposite\text{ of angle u}}{\text{hypotenuse}}=\frac{2}{5} \\ \tan v=\frac{opposite\text{ of angle v}}{\text{hypotenuse}}=\sqrt[]{21} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csin%20u%3D%5Cfrac%7Bopposite%5Ctext%7B%20of%20angle%20u%7D%7D%7B%5Ctext%7Bhypotenuse%7D%7D%3D%5Cfrac%7B2%7D%7B5%7D%20%5C%5C%20%5Ctan%20v%3D%5Cfrac%7Bopposite%5Ctext%7B%20of%20angle%20v%7D%7D%7B%5Ctext%7Bhypotenuse%7D%7D%3D%5Csqrt%5B%5D%7B21%7D%20%5Cend%7Bgathered%7D)
So we can go ahead and label the sides of the triangle as shown below;
We can find the value of u as shown below;

We can find v as shown below;
It only has one line of symmetry
For two triangles to be congruent, we need to show is two of the
1. corresponding angles are congruent,
or,
2. all three pairs of corresponding sides are proportional,
or
3. two pairs of corresponding sides are proportional AND the included angles are congruent.
Choice D saus, angles Q and Q' are congruent, angles R and R' are congruent, therefore satisfies the first criterion that at least two corresponding angles are congruent.