R^4-2(r-14)>0
r^4-2r+28>0
r^4-2r+28=0
There is no real solution but there is all real numbers
:)
Answer:
Check explanations
Step-by-step explanation:
For all real numbers a,b, and c, the distributive property states that:

For Part A, we have

Or

For Part B, we have
-4(3x-10)+5(2-6x)=-4*3x--4*10+5*2-5*6x
This simplifies to:
-4(3x-10)+5(2-6x)=-12x+40+10-30x
-4(3x-10)+5(2-6x)=-12x-30x+40+10
-4(3x-10)+5(2-6x)=-42x+50
For the C part, we have:



For Part D, we have:

We simplify to get:

Simplify further to get:

<span>inversely
y = k/x
k = yx
k = 10*10 = 100
when y = 20
20 = 100/x
20x = 100
x = 5
answer
</span><span> x = 5 when y is 20</span>
Answer:
(7,4)
Step-by-step explanation:
midpoint formula (x1+x2)/2 , (y1+y2)/2
Look at x and y for the endpoints separately
midpoint x value = ( 1 + x)/2
4= (1 + x)/2
8 = 1 + x
x = 7
midpoint y value = (2 + y)/2
3 = (2 + y)/2
6 = 2 + y
y = 4
endpoint (x,y) = (7,4)