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ollegr [7]
3 years ago
12

42 =3(2 – 3h) how do you distributive property

Mathematics
2 answers:
ivann1987 [24]3 years ago
6 0

Answer:

h = -4

Step-by-step explanation:

Natali5045456 [20]3 years ago
4 0

Answer:

To do distributive property, you just multiply the outside number by everything in the parenthesis.

Step-by-step explanation:

I'm going to flip it around, because I like it better that way. Okay, so:

3(2 - 3h) = 42. First, 3 times 2 makes 6. Next, 3 times 3h makes 9h. So, we can  now simplify. 6 - 9h = 42. Next, we subtract 6 from both sides of the equation, because we want to get our variable alone on one side. 6 is positive, so we have to subtract it. We get -9h = 36. Next, we divide by -9, to get that variable alone and positive. So, h = -4.

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Simplify (-6) = 3 would be false.

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What is two time four
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Mark bought 2 pounds of walnuts for 25.50 Approximately how much will he pay for 7 pounds of walnuts​
lara31 [8.8K]

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89.25

Step-by-step explanation:

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3 0
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What is the answer to 3/x=-3/3x+5
Aleonysh [2.5K]

Answer:

-\frac{5}{4} =x

Step-by-step explanation:

We first need to bring x up into the numerator. I will find common denominators by multiplying both sides by each denominator.

\frac{x(3x+5)}{1} *\frac{3}{x} =\frac{-3}{3x+5}*\frac{x(3x+5)}{1}

This will eliminate both denominators and leave me with

(3x+5)3=-3(x)\\9x+15=-3x after I simplify the parenthesis.

Now I will solve the equation for x by subtracting 9x from both sides.

9x-9x+15=-3x-9x\\15=-12x

Then divide by the coefficient of x.

\frac{15}{-12}=\frac{-12x}{-12}

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7 0
3 years ago
Solve the system of equations 2x+4y+3z=6 5x+8y+6z=4
MaRussiya [10]

Answer:Solution :

{x,y,z} = {-8,52/7,-18/7}  

 

System of Linear Equations entered :

  [1]    2x + 4y + 3z = 6

  [2]    5x + 8y + 6z = 4

  [3]    4x + 5y + 2z = 0

Solve by Substitution :

// Solve equation [3] for the variable  z  

 

 [3]    2z = -4x - 5y  

 [3]    z = -2x - 5y/2  

// Plug this in for variable  z  in equation [1]

  [1]    2x + 4y + 3•(-2x-5y/2) = 6

  [1]    -4x - 7y/2 = 6

  [1]    -8x - 7y = 12

// Plug this in for variable  z  in equation [2]

  [2]    5x + 8y + 6•(-2x-5y/2) = 4

  [2]    -7x - 7y = 4

// Solve equation [2] for the variable  y  

 

 [2]    7y = -7x - 4

 [2]    y = -x - 4/7

// Plug this in for variable  y  in equation [1]

  [1]    -8x - 7•(-x -4/7) = 12

  [1]    -x = 8

// Solve equation [1] for the variable  x  

  [1]    x = - 8  

// By now we know this much :

   x = -8

   y = -x-4/7

   z = -2x-5y/2

// Use the  x  value to solve for  y  

   y = -(-8)-4/7 = 52/7  

// Use the  x  and  y  values to solve for  z  

 z = -2(-8)-(5/2)(52/7) = -18/7  

Solution :

{x,y,z} = {-8,52/7,-18/7}  

Step-by-step explanation:

4 0
3 years ago
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