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3 years ago

Choose the correct elements in the set for the following:

Mathematics

1 answer:

Ber [7]3 years ago

8 0

Answer:

Step-by-step explanation:

Y => - 3 that is {−3, −2, −1, 0, . . .}

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100 is 10 more than my number

mixer [17]

The answer to your problem is 90 because 100 minus 10 is 90

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3 years ago

Review

Iteru [2.4K]

Answer:

300 meters

Step-by-step explanation:

250+150+50+x=750

450+x=750

x=750-450=300

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3 years ago

In Exercise, find the derivative of the function.<br> y = 3ex - xex

nevsk [136]

Answer:

the question is incomplete, the complete question is "find the derivative of the function $y=3e^{x}-xe^{x}$ "

answer: $\frac{dy}{dx}=(2-x)e^{x}$ .

Step-by-step explanation:

From the equation, $y=3e^{x}-xe^{x}$ , we approach the question using the differentiation of a product and differentiation of a sum simultaneously,

the differentiation of a sum is express as

f(x)=u(x)+v(x)+.....w(x) then

$\frac{df(x)}{dx}=\frac{du(x)}{dx}+\frac{dv(x)}{dx}+...\frac{dw(x)}{dx}.\\$

For the differentiation of a product we have

f(x)=u(x)v(x), then

$\frac{df(x)}{dx}=\frac{dv(x)}{dx}u(x)+\frac{du(x)}{dx}v(x)$

hence if we go by the formula we arrive at

for $y=3e^{x}$

let u(x)=3 hence du/dx=0 and

$v(x)=e^{x}$ and $\frac{dv(x)}{dx}=e^{x}$

hence $\frac{dy}{dx}=3e^{x}+0e^{x}\\\frac{dy}{dx}=3e^{x}---equation 1\\$

Also for $y=-xe^{x}\\\frac{dy}{dx}=-e^{x}-xe^{x}---equation 2$ .

if we add equation 1 and equation 2 we arrive at

$\frac{dy}{dx}=3e^{x}-e^{x}-xe^{x}\\\frac{dy}{dx}=(3-1-x)e^{x}\\\frac{dy}{dx}=(2-x)e^{x}$ .

4 0

3 years ago

(Giving brainliest to correct answer)<br><br> Congruence

Aleksandr [31]

Answer:СССР в зеркале

Кто первый спустит курок

Убеждаешь - ложно заявляя свободу личности.

Бушующие войны и П-С-О,

Космос, О-С-В

Брежнев Рейган

Страх оружия С-Я-С

До взаимного уничтожения

Силой и мощью

Союза Советских Республик

Патриоты работают силой порядка

Светлое строят будущее

Наука, Творчество, Семья, Союз,

Образование, Коммуналка, Труд,

Дисциплина, Планировка, Доброта.

Родина – поём тебе,

В верности клянёмся,

Пролетарии всех стран Соединяйтесь

Серп и Молот!

Step-by-step explanation:

3 0

3 years ago

The class sizes of the introductory psychology courses at a college are shown below 121,134,106,93,149,130,119,128 the college a

frozen [14]

Center : Mean Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5 After the introduction of the new course, center = average(121,134,106,93,149,130,119,128,45) = 113.9 The center has moved to the left (if plotted in a graph) because of the low intake for the new course. Spread before introduction of the new course : Arrange the numbers in ascending order: (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132 Spread = Interquartile range = Q3-Q1 = 19.5 After addition of the new course,

(45,93, 106,119,) 121, (128, 130,134, 149)
Q1=median(45,93,106,119)=99.5
Q3=median (128, 130,134, 149)= 132
Spread = Interquartile range = 132-99.5 =32.5
We see that the spread has increased after the addition of the new course.

3 0

4 years ago

Read 2 more answers