Answer:
807.8 in^2
Step-by-step explanation:
The total area of the box is the sum of the areas of all faces of the box. The top, bottom, front, and back faces are rectangles 18 in long. The end faces each consist of a rectangle and a triangle. We can compute the sum of these like this:
The areas of top, bottom, front, and back add up to be 18 inches wide by the length that is the perimeter of the end: 2·5in +2·8 in + 9.6 in = 35.8 in. That lateral area is ...
(18 in)(35.6 in) = 640.8 in^2
The area of the triangle on each end is equivalent to the area of a rectangle half as high, so we can compute the area of each end as ...
(9.6 in)(8.7 in) = 83.52 in^2
Then the total area is the lateral area plus the area of the two ends:
640.8 in^2 + 2·83.52 in^2 = 807.84 in^2 ≈ 807.8 in^2
Problem One
Find AM
AM = 71.5 - 22 = 49.5
Step Two
State the Givens.
AM = 49.5
MN = 71.5
MB = x
MP = 97.5
Step Three
Set up the Proportion
AM : NM :: x : PM
49.5 : 71.5 :: x : 97.5
Substitute and solve
49.5 / 71.5 = x / 97.5 Cross Multiply
49.5 * 97.5 = 71.5 * x Combine the numbers on the left.
4860.375 = 71.5 * x Divide by 71.5
4860.375 / 71.5 = x
x = 67.98
Problem Two
Remark
This is just a straight application of the Pythagorean Theorem
a^2 + b^2 = c^2
a = 10
b = 24
c = ??
10^2 + 24^2 = c^2
100 + 576 = c^2
676 = c^2
sqrt(c^2) = sqrt(676)
c = 26 <<<< answer
-10 and -2
Because -10-2= -12 and -10 x -2 = 20
Hope this helps :)
Answer:
6y+3xy
Step-by-step explanation:
You can combine the y's together to get this answer
The perpendicular line to x-6y=2, and passing through (2, 4) is y=-6x+16
