A couch regularly sells for $840. The sale price is $714. Find the percent decrease of the sale price from the regular price

Stan's Sweater Superstore has a 30% off sale. This week only, everything in the store is marked down an additional 10% off the s

evablogger [386]

Answer:

$30

Step-by-step explanation:

30 % + 10 % = 40 %

40 % of $50 = $20

%50 - $20 = $30

8 0

3 years ago

PLEASE HELP PLEASEEEE!!! Number 3

deff fn [24]

The equation for this is a^2+b^2=c^2 so your equation would be 7^2+20^2=X
So you square the 7 and the 20 then take the square root of X and you get
X=21.19
:)

6 0

3 years ago

What is the nth term of the geometric sequence -2,10,-50

poizon [28]

Answer:

$T_n=-1(-5)^n^-^1$

Step-by-step explanation:

We are given;

A geometric sequence;

-2,10,-50

Required to determine the nth term

The nth term in a geometric sequence is given by the formula;

$T_n=a_1r^n^-^1$

where $a_1$ is the first term and r is the common ratio;

In this case;

$a_1=-2$

r = 10 ÷ -2

= -5

Therefore;

To get the nth term in the given geometric sequence we use;

$T_n=-1(-5)^n^-^1$

Thus, the nth term is $T_n=-1(-5)^n^-^1$

3 0

2 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

2 years ago

Which of the following angles can be added together to create 132°? Explain your answer using words.

seropon [69]

Answer:

52,25,30,35 is the answer

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers