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inysia [295]
3 years ago
11

What does 54 round to

Mathematics
1 answer:
AleksAgata [21]3 years ago
8 0
It rounds to 50 because the back number is below the 5
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I don't know how to do this. Can someone explain how to please?​
Natalija [7]

Answer:

f(5) = -2

Step-by-step explanation:

You look on the x-axis for 5 because f(5) means let x = 5. Then go down to the graph (the red zig-zaggy line) At the red line (you're still directly under the 5) look over to the y-axis to find the value. That's your answer. It is -2. The point (5, -2) is on the red graph.

f(5) = -2

3 0
2 years ago
If anyone could help?
Trava [24]

Answer:

y=\frac{5}{7}x and y=\frac{7}{9}x

Step-by-step explanation:

A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.

In y=\frac{5}{7}x when x=3, y=15/4≈2.14

In y=\frac{3}{5}x when x=3, y=1.8

In y=\frac{7}{9}x when x=3, y≈2.33

In y=\frac{7}{11}x when x=3, y≈1.90

We can observe that in two cases, y=\frac{5}{7}x and y=\frac{7}{9}x, y is greater than 2.


5 0
3 years ago
In each case use the new theorems to arrange the letters measures from greatest to least
tino4ka555 [31]

Answer:

answer is a,b,c

Step-by-step explanation:

7 0
2 years ago
S: 12b - 3 = 106 + 9​
Sedaia [141]
I got 9.8 but if you want to round it you get 10 because you add 106 and 9 to get 115 and then add 3 and get 118 and then divide 12b and 118 and get 9.8
4 0
3 years ago
Use the rational zeroes theorem to state all the possible zeroes of the following polynomial:
Mkey [24]

Answer:

All the possible zeroes of the polynomial: f(x) = 3x^{6} + 4x^{3} - 2x^{2} +4 are  ±1 , ±2 ,  ±4 ,  ±\frac{1}{3} , ±\frac{2}{3}  , ±\frac{4}{3} by using rational zeroes theorem.

Step-by-step explanation:

Rational zeroes theorem gives the possible roots of polynomial f(x) by taking ratio of p and q where p is a factor of constant term and q is a factor of the leading coefficient.

The polynomial f(x) = 3x^{6} + 4x^{3} - 2x^{2} +4

Find all factors (p) of the constant term.

Here we are looking for the factors of 4, which are:

±1 , ±2 and ±4

Now find all factors (q) of the coefficient of the leading term

we are looking for the factors of 3, which are:

±1 and ±3

List all possible combinations of ± \frac{p}{q}  as the possible zeros of the polynomial.

Thus, we have ±1 , ±2 ,  ±4 ,  ±\frac{1}{3} , ±\frac{2}{3}  , ±\frac{4}{3} as the possible zeros of the polynomial

Simplify the list to remove and repeated elements.

All the possible zeroes of the polynomial: f(x) = 3x^{6} + 4x^{3} - 2x^{2} +4 are  ±1 , ±2 ,  ±4 ,  ±\frac{1}{3} , ±\frac{2}{3}  , ±\frac{4}{3}

Learn more about Rational zeroes theorem here -https://brainly.ph/question/24649641

#SPJ10

7 0
2 years ago
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