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777dan777 [17]
3 years ago
8

Jack and Peter each have the same amount of money in their wallets. They went to the store together and decided to buy some cook

ies, splitting the cost equally. After buying the cookies, do they still have the same amount of money in their wallets?
What Property is relevant to help you decide?
Mathematics
2 answers:
Free_Kalibri [48]3 years ago
7 0

Answer:

Yes they do.

Step-by-step explanation:

You know this because if they show up to the store with the same amount of money and SPLIT the amount of money for the cookies, they will still have the exact same amount.

hjlf3 years ago
4 0

Answer:

yes

Step-by-step explanation:

i think division property since they split the amount of money

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Please help ASAP
belka [17]

Answer:

Option B is correct

Step-by-step explanation:

Hope that helped u

6 0
3 years ago
In AJKL, the measure of ZL=90°, JL = 55, LK = 48, and KJ = 73. What
Juli2301 [7.4K]
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3 0
2 years ago
Factorise 2x^2 - 3x -2 < 0
Galina-37 [17]
Step 1: Factor 2 x^{2} - 3x -2
1. <span> Multiply 2 by -2, which is -4.</span>
2. <span>Ask: Which two numbers add up to -3 and multiply to -4?
</span>3. <span>Answer: 1 and -4
</span>4. Rewrite -3x as the sum of x and -4x

2 x^{2} +x-4x-2\ \textless \ 0


Step 2: <span>Factor out common terms in the first two terms, then in the last two terms.

</span>x(2x+1)-2(2x+1)\ \textless \ 0
<span>
Step 3: </span>Factor out the common term 2x+1

(2x+1)(x-2)\ \textless \ 0

Step 4: Solve for x

1. Ask: When will (2x+1)(x-2) equal zero?
2. Answer: When 2x + 1 = 0 or x-2=0
3. <span>Solve each of the 2 equations above:

</span>x=- \frac{1}{2} ,2
<span>
Step 5: </span>From the values of x <span>above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: P</span><span>ick a test point for each interval

</span>For the interval x\ \textless \ - \frac{1}{2} &#10;
Lets pick x=-1. Then, 2(-1) ^{2} -3 * -1 -2 \ \textless \  0
After simplifying, we get 3\ \textless \ 0, Which is false. 
Drop this interval.
<span>
For this interval - \frac{1}{2} \ \textless \ x\ \textless \ 2
Lets pick x=0. Then, 2* 0^{2} - 3 * 0-2\ \textless \ 0. After simplifying, we get -2\ \textless \ 0, which is true. Keep this <span>interval.

For the interval </span>x\ \textgreater \ 2

Lets pick x = 3. Then, 2 * 3  ^{2} -3*3-2\ \textless \ 0. After simplifying, we get 7\ \textless \ 0, Which is false. Drop this interval.

.Step 7: Therefore, 
- \frac{1}{2} \ \textless \ x\ \textless \ 2

Done! :)</span>
4 0
3 years ago
(5x^2-4X + 7) - (4x + 2)
DanielleElmas [232]
5x’2-4x+7-4x-2
We add the two 4
5x’2-8x+7-2
5x’2-8x+5
The answer is
5x’2 -8x +5
3 0
3 years ago
Evaluate the expression for<br> x = 6, y = -10:<br> 3x - 7y
Natasha_Volkova [10]

Answer:

88

Step-by-step explanation:

hello,

we need to replace x by 6 and y by -10 so it comes

3*(6)-7*(-10)

= 18 + 70 = 88

hope this helps

8 0
3 years ago
Read 2 more answers
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