Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then
By substitution, we have that
and
.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
Answer: The required values are
f(-2) = 120, f(0) = 64 and f(1) = 84.
Step-by-step explanation: We are given the following function f(x) :
We are to find the values of the following :
To find the values of the function at the given points, we need to substitute the corresponding values of x in equation (i).
Substituting x = -2 in equation (i), we get
Substituting x = 0 in equation (i), we get
Substituting x = 1 in equation (i), we get
Thus, the required values are
f(-2) = 120, f(0) = 64 and f(1) = 84.
1. less than ( I gave x a number and did both equations )
2. the equation = 400 which is greater than 35
Answer:
first of all, the graphs are so poorly plotted,even kn computer...
anyways,
since the blue one ending at x=5 on the x axis,
while actual log ends at x=0 this means
X=x-5
and since, log1=0 but it's 5 in blue graph,
the graph is moved up by 5
hence,
y=5+log(x-5)