Hello from MrBillDoesMath!
Answer: infinite solutions
Discussion: I did a double take on this one but the left hand is
a + 3 + 2a = 3a +3
and the right hand side is
-1 + 3a + 4 = 3a + (4-1) = 3a + 3
The left and right sides of the equation are identical for all "a", i.e. for infinitely many "a" values.
Regards, MrB.
Answer:
r=4
Step-by-step explanation:
15r-6r=36
9r=36
r=36/9
r=4
Answer: a6=70
Step-by-step explanation:
we know that
In the Arithmetic Sequence the formula is:
an= a1 + d(n−1)
where
a1 is the first term
d is the common difference
n is the number of terms
in this problem
a1=5
a2=18
a3=31
a4=44
a5=57
so
d=a2-a1 or a3-a2 or a4-a3 or a5-a4
d=57-44----> 13
find a6
a6= a1 + d(n−1)
n=6
d=13
a1=5
a6=5+13*(6-1)----> a6=5+13*5----> a6=70
Whats the question for this question