Answer:
21.6 g
Explanation:
The reaction that takes place is:
First we<u> convert the given masses of both reactants into moles</u>, using their <em>respective molar masses</em>:
- 9.6 g CH₄ ÷ 16 g/mol = 0.6 mol CH₄
- 64.9 g O₂ ÷ 32 g/mol = 2.03 mol O₂
0.6 moles of CH₄ would react completely with (2 * 0.6) 1.2 moles of O₂. As there are more O₂ moles than required, O₂ is the reactant in excess and CH₄ is the limiting reactant.
Now we <u>calculate how many moles of water are produced</u>, using the <em>number of moles of the limiting reactant</em>:
- 0.6 mol CH₄ *
= 1.2 mol H₂O
Finally we<u> convert 1.2 moles of water into grams</u>, using its <em>molar mass</em>:
- 1.2 mol * 18 g/mol = 21.6 g
The new pressure will be 7.65 atm
<h3>General gas law</h3>
The problem is solved using the general gas equation:
P1V1/T1 = P2V2/T2
In this case, P1 = 3.4 atm, V1 = 1500 mL, T1 = 25 
, V2 = 2000 mL, and T2 = 75
What we are looking for is P2.
Thus, P2 = P1V1T2/T1V2
= 3.4 x 1500 x 75/25 x 2000 = 382500/50000 = 7.65 atm
More on general gas laws can be found here: brainly.com/question/2542293
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Answer:
A.
Explanation:
melting of ice will increase water in oceans due to which water in oceans will increase and salinity will decrease. hence, melting of ice caps near the north pole affects salinity of the ocean
Explanation:
1 mole of a gas has 22.4 L of volume at STP. Therefore, 0.5 mol of H2 has 0.5 x 6.022 x 1023 = 3.011 x 1023 molecules. Hence, the number of moles, molecules and atoms present in 11.2 liters of H2 at STP are 0.5 , 3.011 x 1023 and 6.022 x 1023 respectively.
Answer:
pH = 5.58
Explanation:
Given that :
Citric acid is a triprotic acid with the formula 
. Tripotic acids are acids that have the tendency to yield three protons per molecule during the phases of dissociation, therefore they have three pka.
For Citric acid; the pka values are:
So, the pH of sodiummonohydrogencitrate with the chemical formula 
which can act as an acid and a base (i.e it is said to be amphoteric) can be calculated as :
pH = 5.58
Therefore, the approximate pH of a solution of sodium monohydrogencitrate = 5.58
