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erastova [34]
3 years ago
10

Citric acid, also known as vitamin C, is a triprotic acid with the formula H3C6H5O7. The pKa values are 3.13, 4.76, and 6.40. Wh

at will be the approximate pH of a solution of sodium monohydrogencitrate, Na2HC6H5O7?
Chemistry
1 answer:
Ronch [10]3 years ago
5 0

Answer:

pH = 5.58

Explanation:

Given that :

Citric acid  is a triprotic acid with the formula H_3C_6H_5O_7 . Tripotic acids are acids that have the tendency to yield three protons per molecule during the phases of dissociation, therefore they have three pka.

For Citric acid; the pka values are:

pKa _1 = 3.13\\pKa_2 = 4.76\\pKa_3 = 6.40

So, the pH of sodiummonohydrogencitrate with the chemical formula Na_2HC_6H_5O_7 which can act as an acid and a base (i.e it is said to be amphoteric) can be calculated as :

pH = \frac{pKa_2+pKa_3}{2}

pH = \frac{4.76+6.40}{2}

pH = 5.58

Therefore, the approximate pH of a solution of sodium monohydrogencitrate = 5.58

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