Answer:
The solution of given equation for x is (0.16 + i 1.14) , (0.16 - i 1.14)
Step-by-step explanation:
Given as :
The quadratic equation is as 3 x² - x + 4 = 0
Since The given equation is quadratic
∵, Standard quadratic equation is ax² + bx + c = 0
Now, x = 
<u>Comparing the equation</u>
i.e x = 
or, x = 
Or, x = 
Or, x = 
Or, x = (0.16 + i 1.14) , (0.16 - i 1.14)
So, The solution of given equation for x = (0.16 + i 1.14) , (0.16 - i 1.14)
Hence, The solution of given equation for x is (0.16 + i 1.14) , (0.16 - i 1.14) . Answer