All categories

3 years ago

Plz help asappppppppp!!!

Mathematics

1 answer:

MAVERICK [17]3 years ago

8 0

Answer:

10, 22, 48.4, 106.48, 234.256

Step-by-step explanation:

The first term is already given it is 10.

The second term is the first term times 2.2.

10×2.2=22

The second term is 22.

The third term is the second term times 2.2.

22×2.2=48.4

The third term is 48.4.

The fourth term is the third term times 2.2.

48.4×2.2=106.48

The fourth term is 106.48.

The fifth term is the fourth term times 2.2.

106.48×2.2=234.256

The fifth term is 234.256.

You might be interested in

Help no time plzzzz plz plz

Sav [38]

Answer:

FALSE

Step-by-step explanation:

<E in ∆AED ≅ <E in ∆CEB.

Both are 90°.

Side ED ≅ Side EB

Side AD ≅ Side CB.

Thus, two sides (ED and AD) and a non-included angle (<E) of ∆AED are congruent to corresponding two sides (EB and CB) and a non-included angle (<E) of ∆CEB. Therefore, by A-S-S Congruence Theorem, both triangles are congruent to each other not by SSS.

8 0

3 years ago

PLEASE I REALLY NEED HELP!!! DUE SOON

maria [59]

Answer:

69.08

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Factor-

Nastasia [14]

Hello from MrBillDoesMath!

Answer:

See Discussion section below

Discussion:

2x^2 + 5x + 3 = (2x+3)(x+1) which is Choice 3

3x^2+10x+4 =-1/3 (-3 x + sqrt(13) - 5) (3 x + sqrt(13) + 5)

I don't think any of the provided choices are right!

8x^2+10x-3 = (2x+3)(4x-1) which is Choice 2

6x^2-7x-4 = -1/24 (-12 x + sqrt(145) + 7) (12 x + sqrt(145) - 7)

I don't think any of the provided choices are right!

2x^2+x-28 = (2x-7)(x+4) which is Choice 2

Thank you,

MrB

4 0

3 years ago

How do i solve 7x^{2} +11y^{2} =40

svetoff [14.1K]

Answer:

Step-by-step explanation:

There is no solution as you have two variables and only one equation. The best you can do is solve for one variable as a function of the other.

$7x^2+11y^2=40\\ \\ 11y^2=40-7x^2\\ \\ y^2=\frac{40-7x^2}{11}\\ \\ y=\sqrt{\frac{40-7x^2}{11}}$

6 0

3 years ago

Stella needs fencing for the perimeter of a

Crazy boy [7]

Answer:

$\boxed{Fencing \: need \: to \: buy \: for \: the \: entire \: perimeter = \frac{40}{3} \: yards}$

Step-by-step explanation:

Length of rectangular garden (l) = 16 feet

Width of rectangular garden (w) = 4 feet

$3 \: feet = 1 \: yard \\ \\ 1 \: feet = \frac{1}{3} \: yard$

$\\ = > Perimeter \: of \: rectangular \: garden = 2(l + w) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2(16 + 4) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times 20 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 40 \: feets \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =40 \times \frac{1}{3} \: yards \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{40}{3} \: yards$

4 0

4 years ago