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morpeh [17]
3 years ago
11

Plz help asappppppppp!!!

Mathematics
1 answer:
MAVERICK [17]3 years ago
8 0

Answer:

10, 22, 48.4, 106.48, 234.256

Step-by-step explanation:

The first term is already given it is 10.

The second term is the first term times 2.2.

10×2.2=22

The second term is 22.

The third term is the second term times 2.2.

22×2.2=48.4

The third term is 48.4.

The fourth term is the third term times 2.2.

48.4×2.2=106.48

The fourth term is 106.48.

The fifth term is the fourth term times 2.2.

106.48×2.2=234.256

The fifth term is 234.256.

You might be interested in
14. Find mMK please :)
MrRissso [65]

Answer:

Step-by-step explanation:

11) strategy:  since they tell us. indirectly,  that the length of  JK is the same as LM then we can set those two equal, solve for X  and then.. when we have X we can figure out the lenght of JK  and LM and then just divide that by 2 go get PK  ( :0 Player Killer ???  no , not that PK)    

solve JK and LM

3x + 23 =9x-19

42 = 6x

7 = x

now that we know x = 7 plug it into either equation to come up with the length of JK or LM .  I'll pick JK just b/c it was 1st

3(7) + 23 = JK

21+23 = JK

44 = JK

now take half of 1/2*JK= 22  that is PK    ( are you sure that 's not player killer?)

PK = 22

12) strategy: set the two arcs BG and GC equal and solve for X, then plug x into either equation and the multiply the answer by 2 to find arc AB

9x-20 = 5x + 28

4x = 48

X = 12

9(12) -20 = BG

88 = BG

2*88 + AB

176 = AB

13) done

14)  strategy: find the angle at L,  and that will also be the arc of MK

<em>copy and past the below</em> helpful trig functions into your computer

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

<em>copy and past the above</em> :

use which ever trig function you want , we have all the sides of the triangle, I'll use CAH

Cos(Ф) = 9/15

Ф = arcCos(9/15)

Ф = 53.13010°

arc MK = 53.13010°

15)   strategy:  arc JK is just 2 times MK

2*MK = 106.26020°

arc MK = 106.26020°

16) find arc JPK   strategy:  JPK is just the remaining part of a full circle of 360 - MK  = 253.7397°

arc JPK = 253.7397°

7 0
3 years ago
The hypotenuse of an isosceles right triangle is 16 centimeters. Find the length of the 2 other sides of the triangle to the nea
scZoUnD [109]
Right triangle means we can use a^2+b^2=c^2
isosceles means 2 sides are equal legnths

the hypotenuse is normally the longest side so the equal sides are the other sides so therefore
a=b
therefor
(a^2)+(a^2)=c^2
2(a^2)=16^2
2(a^2)=256
divde both sides by 2
a^2=8
the side legnth of the other 2 sides is the square root of 8 which is aprox 2.8284271247452
but we only want the tenth so we look at the hundreths as well
2.82
round to the nearest tenth
2.8 cm is the answer of the legnths
4 0
3 years ago
In triangle DEF, segment DJ is a perpendicular bisector of side EF. If EJ is 3y-8 and JF is 7y-40, what is the length of JF?
luda_lava [24]

Answer: The length of JF = 16 units.

Step-by-step explanation:

Given: In triangle DEF, segment DJ is a perpendicular bisector of side EF.

i.e. DJ is perpendicular to EF and DJ divides EF into two equal parts EJ and JF. [The perpendicular bisector is a line that is perpendicular to a line segment and splits it into two congruent segments.]

If  EJ is 3y-8 and JF is 7y-40.

Then, 3y-8=7y-40

\Rightarrow\ 7y-3y=40-8\\\\\Rightarrow\ 4y=32\\\\\Rightarrow\ y=8 \text{ [Divide both sides by 4]}

JF= 7(8)-40 =56-40= 16 units

Hence, the length of JF = 16 units.

4 0
3 years ago
Read 2 more answers
The vertices of a triangle are located at the points A(0, 1), B(2, 4) and C(3, 0). The triangle is translated 5 units down to ob
lyudmila [28]

Answer:

The coordinates of the vertices of triangle A'B'C' are A'(x,y) = (0,-4), B'(x,y) = (2,-1) and C'(x,y) = (3,-5).

Step-by-step explanation:

According to this statement, triangle ABC must be translated 5 units in the -y direction to form triangle A'B'C'. We need to use the following operations:

A'(x,y) = A(x,y) +(0,-5) (1)

B'(x,y) = B(x,y) +(0,-5) (2)

C'(x,y) = C(x,y) + (0,-5) (3)

If we know that A(x,y) = (0,1), B(x,y) = (2,4) and C(x,y) = (3,0), then the new  vertices of the rectangle are, respectively:

A'(x,y) = (0,-4), B'(x,y) = (2,-1), C'(x,y) = (3,-5)

8 0
3 years ago
What is the effect on the graph of f(2) g(2) =} - 1? 1 when it is transformed to g(x)=1/x -7
777dan777 [17]

The effect on the graph of f(x)= 1/x when it is transformed to g(x)= 1/x-7 is C. The graph of f(x) is shifted 7 units down.

<h3>What is a graph?</h3>

A graph is a diagram showing the relation between variable quantities, each measured along with one of a pair of axes at right angles.

In this case, the effect on the graph of f(x)= 1/x when it is transformed to g(x)= 1/x-7 is that the graph of f(x) is shifted 7 units down.

The missing options include:

A. The graph of f(x) is shifted 7 units up

B. The graph of f(x) is shifted 7 units to the left

C. The graph of f(x) is shifted 7 units down

D. The graph of f(x) is shifted 7 units to the right.

Learn more about graph on:

brainly.com/question/19040584

#SPJ1

6 0
2 years ago
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