Answer:
i dont know
Step-by-step explanation:
Answer:
It has 0 distinct real number zeros. The function does not touch the x-axis
With

we have

so
has one eigenvalue,
, with multiplicity 3.
In order for
to not be defective, we need the dimension of the eigenspace to match the multiplicity of the repeated eigenvalue 2. But
has nullspace of dimension 2, since

That is, we can only obtain 2 eigenvectors,

and there is no other. We needed 3 in order to complete the basis of eigenvectors.
Answer:
It looks right to me good job