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kenny6666 [7]
3 years ago
15

What’s an expression that represents the product of q and 5 divided by 2.

Mathematics
1 answer:
grandymaker [24]3 years ago
5 0

Answer

2.5q

Explanation

Product means multiplication

(q × 5)/2 = (5q)/2

= 2.5q

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3(x-2) + 7x = 1/2(6x-2)
victus00 [196]

Answer:

x=5/8

Step-by-step explanation:

11x-6=3x-1

-3x        -3x

8x-6=-1

   +6   +6

8x=5

8/8   5/8

x=5/8

7 0
3 years ago
What is 62 divided by 3,186 with work
Alenkasestr [34]
See attached for the work

6 0
3 years ago
Read 2 more answers
What is simplified when -3(2x-y) + 2y+2(x+y) ?
S_A_V [24]

Answer: -x + 4y

Step-by-step explanation:

-3(2x-y) + 2y+2(x+y)

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4 0
3 years ago
NO LINKS OR ANSWERING IF YOU DON'T KNOW!!!!
mestny [16]

9514 1404 393

Answer:

  a, c

Step-by-step explanation:

There are 3 linear factors, so the function is odd degree (cubic). The coefficients of x are all positive, so the function has the general shape of an increasing function, left-to-right. The three linear factors mean that the curve crosses the x-axis 3 times, changing sign each time.

The x-intercepts are the values of x that make the factors zero: -7, 3/2, 5. The shape of the function tells you it will be negative for x < -7. Between -7 and 3/2, it will be positive, since it changes sign at x=-7. It changes sign again at x=3/2, so will be negative for 3/2 < x < 5.

In short, the function will be negative at any point that has an odd number of function zeros to its right (taking multiplicity into account).

The function is negative on intervals (a) and (c).

8 0
3 years ago
Which statement describes the behavior of the function f(x)=<br> 2x<br> 3?<br> 1- x2
hjlf

Answer:

              2x

f(x) = -------------- or   f(x) = 2x / (1-x^2)

          1 - x^2

to eliminate any ambiguity.  The graph of this function passes thru the origin (0,0) and has vertical asymptotes at x = -1 and x = + 1.  The function is negative on (-1,0) and positive on (0,1).  

Additionally, there are two horizontal asymptotes.   As x grows large and negative, f(x) approaches zero from above.  As x grows large and positive, f(x) approaches zero from below.

3 0
3 years ago
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