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Sergeu [11.5K]
3 years ago
7

1. Give state diagrams of DFAs recognizing the following languages. The alphabet is {0, 1}. (a) {w | w is any string except 11 a

nd 111} (b) {w | every odd position of w is a 1}

Computers and Technology
1 answer:
storchak [24]3 years ago
6 0

Answer:

Explanation:

The first diagram shows the DFA that accepts that accepts any string except 11 and 111

The second diagram shows every odd position of w is 1

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Whitepunk [10]

Answer:

Following are the statement in C++ Language is given below

total=0; // variable declaration

cin >> amount; // Read the input

while(amount >=0) //iterating the loop

{

if(amount>0) // checking condition

total=total+amount; // perform operation

}

Explanation:

Following is the description of the statement

  • Declared a variable "total" and initialized with them 0 to them.
  • Read the input in the "amount" variable by using cin.
  • iterating the loop when the amount is greater then 0.
  • Checking the condition if(amount>0) then adding the total variable and amount and storing them into the total variable.

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Press the _______ key to move to the next cell in a row.
slamgirl [31]

Tab is the answer! And it says i need 20 chacters to explain so im writing random stuffff



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Select the correct answer.
Anit [1.1K]

Answer: Steady OR Flashing

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3 years ago
Read 2 more answers
Look at the logic program below. Set a breakpoint after each commented instruction. You can also single step through the program
Goshia [24]

Using programming knowledge, it is possible to use programming logic, we can differentiate and find the terms

<h3>Writing the code and understanding the programming logic:</h3>

<em>.data</em>

<em>sourceword:</em>

<em>.word 0xAB</em>

<em>wordmask:</em>

<em>.word 0xCF</em>

<em>operand:</em>

<em>.long 0xAA</em>

<em>.text</em>

<em>.globl _start</em>

<em>_start:</em>

<em>movw sourceword, %ax # ax=0x00AB ( move the word value of sourceword =0x00AB to ax register.)</em>

<em>movw %ax, %bx # bx=0x00AB ( copy the value of ax to bx register.)</em>

<em>xorw %cx, %cx # cx=0000 ( cx=cx XOR cx, that is clear cx register.)</em>

<em />

<em>andw wordmask, %ax # ax=0x008B ( ax=ax AND wordmask= 0x00AB AND 0x00CF= 0x008B)</em>

<em>orw wordmask, %bx # bx=0x00EF (bx=bx OR wordmask= 0x00AB OR 0x00CF= 0x00EF.)</em>

<em>xorw wordmask, %cx # cx=0x00CF (cx=cx XOR wordmask= 0x0000 XOR 0x00CF=0x00CF.)</em>

<em />

<em>movl operand, %eax # eax=0x000000AA. ( copy the 32-bit value of operand=0x000000AA to eax.)</em>

<em>movl %eax, %ebx # ebx=0x000000AA.( copy the value of eax to ebx.)</em>

<em>movl %eax, %ecx # ecx=0x000000AA. ( copy the value of eax to ecx.)</em>

<em />

<em>shll $3,%eax # eax=0x00000550. ( logical shift left of eax=0x000000AA by 3 bits.)</em>

<em />

<em># 0x000000AA=00000000000000000000000010101010</em>

<em />

<em># =>00000000000000000000010101010000=0x00000550.</em>

<em />

<em>rorl $4,%ebx # ebx=0xA000000A. (Rotate right ebx=0x000000AA by 4 bits.)</em>

<em />

<em># 0x000000AA=00000000000000000000000010101010</em>

<em />

<em>3 =>10100000000000000000000000001010= 0xA000000A.</em>

<em />

<em>sarl %ecx # here the count value to shift the bits not mentioned.</em>

<em />

<em># It is the arithmetic shift right instruction. the shifted left bits filled with MSB bit.</em>

See more about logic program at brainly.com/question/14970713

#SPJ1

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2 years ago
Rewrite the following condition to avoid a possible arithmetic exception:
dangina [55]

Answer:

if (x > 7 && Math.sqrt(x) < 3)

Explanation:

The previous condition checks if the square root of x is less than 3, but this would raise an error if x is a value equal to or less than 0.

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