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Mrrafil [7]
3 years ago
9

I only have a picture so you get a better image

Mathematics
2 answers:
Feliz [49]3 years ago
8 0

Answer:

(15, 16)

Step-by-step explanation:

Find the width and height of the diagram.

27 - 3 = 24

30 - 2 = 28

Find side length of square.

24 ÷ 4 = 6

Find half-width of the diagram.

24 ÷ 2 = 12

Find x coordinate.

3 + 12 = 15

Find y coordinate.

28 ÷ 2 = 14

2 + 14 = 16

Likurg_2 [28]3 years ago
6 0

Answer:

(15,16)

Step-by-step explanation:

C=halfway between A to B

A to B on the x axis goes across by 24

24/2 =12

3+12=15

A to B on the y axis goes up by 28

28/2 = 14

2+14=16

(15,16)

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5 and 6

Step-by-step explanation:

5 and 6

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Is square meters a type of surface area
Irina18 [472]

Yes square meters is a type of surface area.

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Lenny rolls two number cubes. What is the probability that the sum of the numbers Lenny rolls is either 4 or 7?
Mashutka [201]

Probability of an event =


(number of ways the event can happen) / (total number of possible outcomes) .


Well, the total number of possible outcomes is easy. It's


(6 possibilities for the first cube) x (6 possibilities for the 2nd cube)


= 36 total possible ways for two cubes to roll.


Now, how many of those possibilities show either 4 or 7 ?


Well, here's how a 4 can come up:


1 . . . 3

2 . . . 2

3 . . . 1


and here's how a 7 can come up:


1 . . . 6

2 . . . 5

3 . . . 4

4 . . . 3

5 . . . 2

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The probability is (9/36) .


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7 0
3 years ago
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Write an equation of the circle that has a diameter with endpoints (12, 3) and<br> (-18,3).
Mademuasel [1]

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

<h3>Coordinates of center of circle</h3>

Since the endpoints of the diameter are (x₁, y₁) = (12,3) and (x₂, y₂) = (-18,3), the coordinates of the center of the circle are the midpoints of the diameter. So, the midpoints are

  • x = (x₁ + x₂)/2 = (12 + (-18))/2 = (12 - 18)/2 = -6/2 = -3 and
  • y = (y₁ + y₂)/2 = (3 + 3)/2 = 6/2 = 3.

So, the coordinates of the center of the circle are (-3, 3)

<h3>The radius of the circle</h3>

The radius of the circle r = √[(x₁ - h)² + (y₁ - k)²] where

  • (x₁, y₁) = coordinates of end of diameter = (12, 3) and
  • (h, k) = coordinates of center of circle = (-3, 3)

So, substituting the values of the variables into r, we have

r = √[(x₁ - h)² + (y₁ - k)²]

r = √[(12 - (-3))² + (3 - 3)²]

r = √[(12 + 3)² + 0²]

r = √[15² + 0²]

r = √15²

r = 15

<h3>The equation of the circle</h3>

The equation of a circle with center (h,k) is given by

(x - h)² + (y - k)² = r² where r = radius of circle.

Substituting the values of the variables into the equation, we have

(x - h)² + (y - k)² = r²

(x - (-3))² + (y - 3)² = 15²

(x + 3)² + (y - 3)² = 15²

x² + 6x + 9 + y² - 6y + 9 = 225

x² + 6x + y² - 6y + 9 + 9 - 225 = 0

x² + y² + 6x - 6y - 207 = 0

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

Learn more about equation of a circle here:

brainly.com/question/18435467

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2 years ago
Which statements about the graphs of functions g(x) = 4x and f(x) = x are true? Select all that apply.
Makovka662 [10]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
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