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3 years ago

If you have work plz show it but I need help with this anyone?

Mathematics

1 answer:

inysia [295]3 years ago

5 0

1) -31

2)-15

3)-13

4)-7

5) 32

6)-7

7)-23

8) 2

9) 9

10) 10

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Find an equation for the perpendicular bisector of the line segment whose endpoints are (8,-5)(8,−5) and (4,3)(4,3).

Marysya12 [62]

Answer:

$Correct answer\\y=\frac{1}{2} x-4$

Step-by-step explanation:

$y-\frac{-5+3}{2} =\frac{-1}{\frac{3-(-5)}{4-8} } (x-\frac{4+8}{2} )\\y+1=\frac{1}{2} (x-6)\\y=\frac{1}{2} x-4$

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3 years ago

Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra

bearhunter [10]

Answer:

$\frac{dh}{dt}=-\frac{1}{2\pi}cm/min$

Step-by-step explanation:

From similar triangles, see diagram in attachment

$\frac{r}{4}=\frac{h}{16}$

We solve for $r$ to obtain,

$r=\frac{h}{4}$

The formula for calculating the volume of a cone is

$V=\frac{1}{3}\pi r^2h$

We substitute the value of $r=\frac{h}{4}$ to obtain,

$V=\frac{1}{3}\pi (\frac{h}{4})^2h$

This implies that,

$V=\frac{1}{48}\pi h^3$

We now differentiate both sides with respect to $t$ to get,

$\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}$

We were given that water is drained out of the tank at a rate of $2cm^3/min$

This implies that $\frac{dV}{dt}=-2cm^3/min$ .

Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means $h=8cm$ .

We substitute this values to obtain,

$-2=\frac{\pi}{16}(8)^2 \frac{dh}{dt}$

$\Rightarrow -2=4\pi \frac{dh}{dt}$

$\Rightarrow -1=2\pi \frac{dh}{dt}$

$\frac{dh}{dt}=-\frac{1}{2\pi}$

3 0

3 years ago

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jenny tweets 33 times a day. use an algebraic expression to describe the number of posts after any given number of days

soldier1979 [14.2K]

33tweets*x=total number of tweets, where x=days spent tweeting.

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3 years ago

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The product of two numbers is 40. If one of the numbers is 8/15, what is the other number?

Harman [31]

If one number is 8/15, you take the difference which 7/15.

5 0

3 years ago

Multiply. What is the value of the second partial product 27x108

jeyben [28]

<h2>Answer:</h2><h2>The partial products of (27) (108) are 216 , 0 , 27.</h2>

Step-by-step explanation:

To find the value of the second partial product 27x108,

Here the multiplicand = 27

The multiplier = 108

The partial products of the multiplication are :

(27) (8) = 0 2 1 6

(27) (0) = 0 0 0

(27) (1) = 2 7

Adding the terms, we get 2916.

The partial products are 216 , 0 , 27.

5 0

3 years ago