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umka21 [38]
2 years ago
13

How do I solve inscribed angles?

Mathematics
1 answer:
Slav-nsk [51]2 years ago
4 0
The triangles are similar so the angles are equal
2x^2 - 2 = 10x - 2
2x^2 - 2 - 10x + 2 = 0
2x^2 - 10x = 0
2x(x - 5) = 0
2x = 0       OR        x - 5 = 0
x = 0         OR        x = 5
0 doesn't make sense, because IF I plug 0 into 2x^2 - 2 I get a negative number.  We need to use 5 to find the angle measure

2(5^2) - 2 = 2(25) - 2 = 50 - 2 = 48 degrees or the measure of CED
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Tema [17]

Let the number of reserved tickets = x

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8 0
3 years ago
3 determine the highest real root of f (x) = x3− 6x2 + 11x − 6.1: (a) graphically. (b) using the newton-raphson method (three it
Juliette [100K]

(a) See the first attachment for a graph. This graphing calculator displays roots to 3 decimal places. (The third attachment shows a different graphing calculator and 10 significant digits.)

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(d) The function h(x, x+0.01) computes the modified secant method as required by the problem statement. The result of the 3rd iteration is ...

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<em>Comment on these methods</em>

Newton's method can have convergence problems if the starting point is not sufficiently close to the root. A graphing calculator that gives a 3-digit approximation (or better) can help avoid this issue. For the calculator used here, the output of "g(x)" is computed even as the input is typed, so one can simply copy the function output to the input to get a 12-significant digit approximation of the root as fast as you can type it.

The "modified" secant method is a variation of the secant method that does not require two values of the function to start with. Instead, it uses a value of x that is "close" to the one given. For our purpose here, we can use the same h(x1, x2) for both methods, with a different x2 for the modified method.

We have defined h(x1, x2) = x1 - f(x1)(f(x1)-f(x2))/(x1 -x2).

6 0
2 years ago
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Step-by-step explanation:

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J

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I hope this helps. Since there are verticale angles that’s why I added another x.

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