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umka21 [38]
3 years ago
13

How do I solve inscribed angles?

Mathematics
1 answer:
Slav-nsk [51]3 years ago
4 0
The triangles are similar so the angles are equal
2x^2 - 2 = 10x - 2
2x^2 - 2 - 10x + 2 = 0
2x^2 - 10x = 0
2x(x - 5) = 0
2x = 0       OR        x - 5 = 0
x = 0         OR        x = 5
0 doesn't make sense, because IF I plug 0 into 2x^2 - 2 I get a negative number.  We need to use 5 to find the angle measure

2(5^2) - 2 = 2(25) - 2 = 50 - 2 = 48 degrees or the measure of CED
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\rm\displaystyle (x  +  2{)}^{2}  + (y  + 5 {)}^{2}  =  {1}^{}

\rm\displaystyle (x - 7{)}^{2}  + (y  + 3{)}^{2}  =  { 7 }

Step-by-step explanation:

<h3>QUESTION-1:</h3>

we are given the center and the redious of a circle equation

remember that,

\rm\displaystyle E _{c} :(x - h {)}^{2}  + (y - k {)}^{2}  =  {r}^{2}

where (h,k) is the centre coordinate and r is redious of the circle

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\rm\displaystyle (x  +  2{)}^{2}  + (y  + 5 {)}^{2}  =  {1}^{}

<h3>QUESTION-2:</h3>

Likewise

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simplify:

\rm\displaystyle (x - 7{)}^{2}  + (y  + 3{)}^{2}  =  { 7 }

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