Perform the indicated operation. 1/3 · 6/7 A.) 1/7 B.) 2/7 C.) 3/7 D.) 5/7

Answer me pleaseeee..... prime numbers between 1 to 10 ?

Answer:

2, 3, 5, 7

Step-by-step explanation:

prime numbers between 1 to 10 are 2,3,5,7. it's very easy. 1 is not prime number because it behave as both prime and composite.

8 0

1 year ago

A ball is kicked upward with an initial velocity of 32 feet per second. The ball's height, h (in feet), from the ground is model

stellarik [79]

Answer:

1. t = 0.995 s

2. h = 15.92 ft

Step-by-step explanation:

First we have to look at the following formula

Vf = Vo + gt

then we work it to clear what we want

Vo + gt = Vf

gt = Vf - Vo

t = (Vf-Vo)/g

Now we have to complete the formula with the real data

Vo = 32 ft/s as the statement says

Vf = 0 because when it reaches its maximum point it will stop before starting to lower

g = -32,16 ft/s² it is a known constant, that we use it with the negative sign because it is in the opposite direction to ours

t = (0 ft/s - 32 ft/s) / -32,16 ft/s²

we solve and ...

t = 0.995 s

Now we will implement this result in the following formula to get the height at that time

h = (Vo - Vf) *t /2

h = (32 ft/s - 0 ft/s) * 0.995 s / 2

h = 32 ft/s * 0.995 s/2

h = 31.84 ft / 2

h = 15.92 ft

4 0

2 years ago

What is the square root of 5 divided by the square root of 15 and simplify and in fraction form

ozzi

Answer:

$\sqrt{\frac{1}{3} }$

or

$\frac{\sqrt{3} }{3}$

Step-by-step explanation:

The expression $\frac{\sqrt{5} }{\sqrt{15} }$ can be simplified by first writing the fraction under one single radical instead of two.

$\frac{\sqrt{5} }{\sqrt{15} } = \sqrt{\frac{5}{15} }$

5/15 simplifies because both share the same factor 5.

It becomes $\sqrt{\frac{5}{15} } = \sqrt{\frac{1}{3} }$

This can simplify further by breaking apart the radical.

$\sqrt{\frac{1}{3} } = \frac{\sqrt{1} }{\sqrt{3} } = \frac{1}{\sqrt{3} }$

A radical cannot be left in the denominator, so rationalize it by multiplying by √3 to numerator and denominator.

$\frac{1}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} } =\frac{\sqrt{3} }{3}$

4 0

2 years ago

A pet supply chain called Pet City has 5 hamsters and 10 gerbils for sale at its Lanberry location. At its Milford location, the

Vlad1618 [11]

Answer:

Milford location has a higher ratio of hamsters to gerbils.

Step-by-step explanation:

Given:

A pet supply chain called Pet City has 5 hamsters and 10 gerbils for sale at its Lanberry location.

At its Milford location, there are 13 hamsters and 16 gerbils.

Now, to find the location who has a higher ratio of hamsters to gerbils.

Ratio of hamsters to gerbils at Lanberry location = 5:10.

$=\frac{5}{10}=0.50$

Ratio of hamsters to gerbils at Milford location= 13:16.

$=\frac{13}{16} =0.8125$

So, 0.8125 > 0.50.

Thus, 13:16 > 5:10.

Therefore, Milford location has a higher ratio of hamsters to gerbils.

4 0

2 years ago

Sarah is driving. Her distance in km from Tempe after t hours of driving is given by: x = D(t) = 13 + 57t

777dan777 [17]

Answer:

The solutions for your four question problem are:

a) t = D^-1(x) = (1/57)*x -(13/57)

b) t = D^-1(x) = 1 h

c) D^-1(x) represents time.

d) The number of hours of driving needed for Sarah to be x km from Tempe. (option (c))

Step-by-step explanation:

a) Determine a formula in terms of x for: t = D^-1(x)

The distance in km from Tempe after t hours of driving is given by

x = D(t) = 13 + 57t.

We just need to find the value t function of x

x = 13 + 57*t

x -13 = 57*t

57*t = x -13

t = (1/57)*x -(13/57)

We can see the plots of both equation in the picture below.

b) Compute D^-1(70)

Once we find the expression for D^-1(x)

We substitute for x = 70 km

t = D^-1(x) = (1/57)*x -(13/57)

t = D^-1(x) = (1/57)*(70) -(13/57)

t = D^-1(x) = (70/57) -(13/57)

t = D^-1(x) = (1.228) -(0.228)

t = D^-1(x) = 1 h

c) In the expression D^-1(x) : what quantity (distance or time) does the x represent? what quantity (distance or time) does the entire D^-1(x) represent?

x represents Distance in both equations (D(t), and D^-1(x))

t represents Time in both equations (D(t), and D^-1(x))

Since t = D^-1(x),

D^-1(x) represents time.

d) Which of the following statements best describes D^-1(x)?

The number of hours of driving needed for Sarah to be x km from Tempe.

Since, t = D^-1(x), and t represents the amount of time elapsed since Sarah, parted from Tempe, the correct answer is option (c)

The expression for D^-1(x) can be found in the previous answers

t = D^-1(x) = (1/57)*x -(13/57)

The input is x (distance) and the output is t (time)

6 0

3 years ago