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3 years ago

39-53 this is very important for my grades

Mathematics

2 answers:

Lisa [10]3 years ago

7 0

Use photomath , its easier it tells you the steps

LiRa [457]3 years ago

6 0

Well actually I'm doing my own math homework right now but let me see what I can do for you!!!!☺️☺️☺️

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Find the horizontal and vertical asymptotes of f(x). f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the

miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* Lets the meaning of vertical and horizontal asymptotes

- Vertical asymptotes are vertical lines which correspond to the zeroes

of the denominator of a rational function

- A horizontal asymptote is a y-value on a graph which a function

approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

then there is a horizontal asymptote at y = leading coefficient of the

numerator ÷ leading coefficient of the denominator

* Lets solve the problem

∵ $f(x)=\frac{6x}{x+2}$

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ The horizontal asymptote can be described by the line y = 6

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ The vertical asymptote can be described by the line x = -2

6 0

2 years ago

Read 2 more answers

Priya has completed 9 exam questions. This is 60% of the questions on the exam.

Natali [406]

Answer:

Your answer is 15, 100% of the exam is 15 questions.

Step-by-step explanation:

60% x ? = 9

We need to do 9 divided by 60%

Which is actually 9 divided by 60/100.

Which is equal to; (100 x 9) divided by 6.

Which is then 900 divided by 60 which equals 15.

Answer: 15

7 0

2 years ago

Simplify: -0.8b + 4.1c -(-3.2b) - 0.1c

umka21 [38]

-0.8b+4.1c-(-3.2b)-0.1c
-(-3.2b)= 3.2b
4.1c-0.1c=4c
-0.8b+4c+3.2b
-0.8b+3.2b=2.4b

4c+2.4b

3 0

2 years ago

Read 2 more answers

What is the area of the figure?

BartSMP [9]

First solve for 16x20. 16*20= 320 inches. Now subtract the area that is removed, the 8x8 square. 8*8=64. 320-64=256. Our answer is 256in^2.

6 0

2 years ago

Suppose that the given line has a slope of -2/3 and a y-intercept of (0,5/3). which of the following points is also a solution t

otez555 [7]

Answer:

From five given points it is find that points (1 , 1) and (4 , -1) will apply

Step-by-step explanation:

According to question,

Slop of line (m) = $\frac{-2}{3}$

And y-intercept is ( 0, $\frac{5}{3}$ )

So from above slope and points, the equation of line can be written as

y = mx + c

i.e $\frac{5}{3}$ = $\frac{-2}{3}$ x + c

$\frac{5}{3}$ = $\frac{-2}{3}$ (0) + c

$\frac{5}{3}$ = 0 + c

Or, c = $\frac{5}{3}$

A) With points ( 5, $\frac{5}{3}$ )

At x = 5, y = $\frac{-2}{3}$ (5) + $\frac{5}{3}$

or, y = $\frac{-10}{3}$ + $\frac{5}{3}$

so, y = $\frac{-5}{3}$

Hence this points do not apply

B) With points ( 1 , 1 )

At x = 1, y = $\frac{-2}{3}$ (1) + $\frac{5}{3}$

or, y = $\frac{-2+5}{3}$

So, y = $\frac{3}{3}$

y = 1

Hence this points will apply

C) With points ( 4 , -1 )

At x = 4 , y = $\frac{-2}{3}$ (4) + $\frac{5}{3}$

y = $\frac{-8+5}{3}$

y = $\frac{-3}{3}$

So, y= -1

Hence this points will apply

D) With points (-3 ,7)

At x = - 3, y = $\frac{-2}{3}$ (-3) + $\frac{5}{3}$

y = $\frac{14}{3}$

Hence this point will not apply

E) with points (0 , 0)

At x 0, y = $\frac{-2}{3}$ (0) + $\frac{5}{3}$

Or, y = 0 + $\frac{5}{3}$

y = $\frac{5}{3}$

Hence this point will not apply

∴ From above five given points it is find that points (1 , 1) and (4 , -1) apply

Answer

7 0

2 years ago