Answer:
please give me brainlest
Step-by-step explanation:
16 is the answers for the question
recall that when it comes to absolute value expressions, once we remove the bars, it turns always to positive, so | -5 |, the bars go poof, and tada!! 5.
Ie 32^2 - 4ac=0 so ac=256 and a+c=130
So, that means:2 equations ac=256 a+c=130 ie c=130-a
So,a(130-a)=256 so 130a -a^2=256 ie a^2-130a +256=0 (a-2)(a-128)=0
Finally,giving a= 2 or a=128 so, a=2 c=128 or a=128 c=2
Since, a>c , a=128 and c=2 ie (128,2)
1/3 = 10/30
2/5 = 12/30
1/6 = 5/30
sum of all of them = 27/30
the fraction that chose the lime sublime is 1/10
The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is 
Step-by-step explanation:
We need to find a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3.
If -1, 1 and 3 are real zeros, it can be written as:
x= -1, x= 1, and x = 3
or x+1=0, x-1=0 and x-3=0
Finding polynomial by multiply these factors:

So, The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is 
Keywords: Real zeros of Polynomials
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