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Readme [11.4K]
3 years ago
5

Researchers want to determine if caffeine affects reaction time. They divide a sample of 150 people into 3 groups. Group 1 gets

a regular drink with no caffeine, group 2 gets a drink with 95 mg of caffeine, and group 3 gets a drink with 250 mg of caffeine. Each group is then given a test to gauge their reaction time. What is the appropriate test to use?
Mathematics
1 answer:
11111nata11111 [884]3 years ago
7 0

Answer:

One-way ANOVA

Step-by-step explanation:

One-way ANOVA(analysis of variance) a testing method in statistics that is used to compare the means of two or more independent samples, to check if the differences are statistically significant.

In this case, we have three groups which their various reaction time to caffeine is to be tested using the same testing method (amount of caffeine). Hence the appropriate test to use here is the one-way ANOVA

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How do you solve an inequality that has a fraction (with a variable as the nemurator/demoninator
vichka [17]

Answer:

Solving with an equality is just simply the same as solving any algebra equations. If you were given a fraction, then just multiply both sides.

Example:

4 + \frac{x}{2} > 14

Subtract 4 on both sides:

4 - 4 + \frac{x}{2} > 14 - 4

\frac{x}{2} > 10

Now <em>multiply both sides by 2</em>:

\frac{x}{2} × 2 > 10 × 2

x > 20

3 0
3 years ago
b) If parametric equations of a flow line are x = x(t), y = y(t), explain why these functions satisfy the differential equations
sineoko [7]

Answer:

The equation of the the flow line that passes through the point (x, y) = (−1, −1) is

In y + In x = 0 or in another form, xy = 1.

Step-by-step explanation:

The pathline equation for a vector field is given by F(x,y) = xî - yj

The velocity vector field for the streamline of the flow is given by

V(x, y) = (dx/dt)î + (dy/dt)j

From the question, it is given that

(dx/dt) = x

(dy/dt) = -y

Hence, the velocity vector field for the streamline of the flow in question is

V(x, y) = xî - yj

which coincides with the pathline vector field of the flow.

The only time the pathline and streamline vector field coincide and have the same equation is when the flow is a steady state flow.

That is, the properties of the fluid flowing isn't changing with time!

Hence, this flow is a steady state flow!

We're told to solve the differential equation.

(dx/dt) = x

(dy/dt) = -y

but

(dy/dx) = (dy/dt) × (dt/dx)

(dy/dx) = -y/x

(dy/y) = -(dx/x)

∫(dy/y) = -∫ (dx/x)

In y = - In x + c

where c is the constant of integration

In y + In x = c

In (xy) = c

Inserting the values of (x, y) given in the question,

In (-1 × -1) = c

In 1 = c

0 = c

c = 0

In y + In x = 0

In (yx) = 0

xy = e⁰ = 1

xy = 1

So, the equation of the the flow line that passes through the point (x, y) = (−1, −1) is

In y + In x = 0 or in another form, xy = 1

Hope this Helps!!!

4 0
3 years ago
There are 12 peaches and 8 bananas in a fruit basket. You get a snack for yourself and three of your friends by choosing of the
muminat

Answer:

10.2% chance

Step-by-step explanation:

There are 12 peaches and 8 bananas for a total of 20 pieces of fruit.

So we can write it:

\frac{12}{20}  *  \frac{11}{19} *  \frac{10}{18} *  \frac{9}{17} =  \frac{11880}{116,280} = .102 or 10.2% chance

For ease multiply all numerators (top numbers) together, then multiply the denominators (bottom numbers) together, and then divide.

12 * 11 * 10 * 9 = 11880

20 * 19 * 18 * 17 = 116,280

We start with 12 peaches and 20 total fruit, as we select a peach the number of peaches and total fruit goes down by one. We do this 4 times because you draw 4 fruits. If you select 1 fruit your chances of it being a peach are 12/20, each time you select a fruit the chances of it being a peach go down because you have 1 less total fruit, and 1 less peach. This is why you multiply each probability together.

6 0
3 years ago
Find the x-Intercept and the y-Intercept of the line below. Click on "None" if applicable.<br> None
PSYCHO15rus [73]

Answer: X-intercept is (2,0)

Y-intercept is (0,-2)

Step-by-step explanation:

3 0
3 years ago
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I need 16 1/5 yards of yarn. I need to make costumes I need 5 2/5 each. How many can I make?
AfilCa [17]

Answer:

the answer is going to 3

8 0
3 years ago
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