Answer:
im pretty sure its 1 mole of sugar
Explanation:
2.05 oz (58.45 g) of salt and 11.98 oz (342.3 g) of sugar
<span>the balanced equation for the reaction is as follows
2C</span>₄H₁₀ + 13O₂ ---> 8 CO₂ + 10H₂<span>O
stoichiometry of C</span>₄H₁₀ to O₂ <span>is 2:13
stoichiometry applies to the molar ratio of reactants and products. Avagadros law states that volume of gas is directly proportional to number of moles of gas when pressure and temperature are constant.
Therefore volume ratio of reactants is equal to molar ratio, volume ratio of C</span>₄H₁₀ to O₂<span> is 2:13
2 L of </span>C₄H₁₀ reacts with 13 L of O₂<span>
then 100 L of </span>C₄H₁₀<span> reacts with 13/2 x 100 = 650 L
therefore 650 L of O</span>₂<span> are required </span>
1. The formula for
absorbance is given as:
A = log (Io / I)
where A is absorbance, Io
is initial intensity, and I is final light intensity
log (Io / I) = A
log (Io / I) = 2
Io / I = 100
Taking the reverse which is
I / Io:
I / Io = 1 / 100
I / Io = 0.01
Therefore this means that
only 0.01 fraction of light or 1% passes through the sample.
2. What is meant by
transmittance values is actually the value of I / Io. So calculating for A:
at 10% transmittance = 0.10
A = log (Io / I)
A = log (1 / 0.10)
A = 1
at 90% transmittance = 0.90
A = log (Io / I)
A = log (1 / 0.90)
A = 0.046
So the absorbance should be
from 0.046 to 1
3. at 10% transmittance =
0.10
A = log (Io / I)
A = log (1 / 0.10)
<span>A = 1</span>
Answer:
ΔH rx = -43.5 kJ / mol
Explanation:
In water, Xdissolves thus:
X(s) + H₂O(l) → X(aq) + H₂O(aq)
It is possible to find the heat in dissolution process using coffee cup calorimeter equation:
Q = -m×C×ΔT
<em>Where Q is heat, m is mass of solution (35.0g -density 1g/mL- + 2.20g = 37.2g), C is specific heat of solution (4.18J/g°C), and ΔT is change in temperature (26.0°C-15.0°C = 11.0°C)</em>
Replacing:
Q = -37.2g×4.18J/g°C×11.0°C
Q = -1710J = -<em>1.71kJ</em>
As enthalpy is the change in heat per mole of reaction, moles of X that reacted were:
2.20g X × (1mol / 56.0g) = <em>0.0393 moles</em>
As heat produced per 0.0393moles was -1.71kJ, heat per mole of X is:
-1.71kJ / 0.0393mol = -<em>43.5 kJ / mol = ΔH rx</em>
The chemical name is ferric oxide or iron (III) oxide or hematite. We can found it naturaly as a magnetite, mineral.
