All categories

3 years ago

1.What percent of light passes through the sample if its absorbance A=2?

Chemistry

1 answer:

Dennis_Churaev [7]3 years ago

3 0

1. The formula for absorbance is given as:

A = log (Io / I)

where A is absorbance, Io is initial intensity, and I is final light intensity

log (Io / I) = A

log (Io / I) = 2

Io / I = 100

Taking the reverse which is I / Io:

I / Io = 1 / 100

I / Io = 0.01

Therefore this means that only 0.01 fraction of light or 1% passes through the sample.

2. What is meant by transmittance values is actually the value of I / Io. So calculating for A:

at 10% transmittance = 0.10

A = log (Io / I)

A = log (1 / 0.10)

A = 1

at 90% transmittance = 0.90

A = log (Io / I)

A = log (1 / 0.90)

A = 0.046

So the absorbance should be from 0.046 to 1

3. at 10% transmittance = 0.10

A = log (Io / I)

A = log (1 / 0.10)

You might be interested in

Combustion analysis is performed on 0.50 g of a hydrocarbon, and 1.47 g of CO2 and 0.902 g of H2O are produced. What is the empi

JulijaS [17]

1. The empirical formula of the hydrocarbon is CH₃

2. The molecular formula of the hydrocarbon is C₂H₆

<h3>How to determine the mass of Carbon </h3>

Mass of CO₂ = 1.47 g
Molar mass of CO₂ = 44 g/mol
Molar of C = 12 g/mol
Mass of C =?

Mass of C = (12 / 44) × 1.47

Mass of C = 0.4 g

<h3>How to determine the mass of H</h3>

Mass of compound = 0.5 g
Mass of C = 0.4 g
Mass of H = ?

Mass of H = (mass of compound) – (mass of C)

Mass of H = 0.5 – 0.4

Mass of H =0.1 g

<h3>1. How to determine the empirical formula </h3>

C = 0.4 g
H = 0.1 g
Empirical formula =?

Divide by their molar mass

C = 0.4 / 12 = 0.03

H = 0.1 / 1 = 0.1

Divide by the smallest

C = 0.03 / 0.03 = 1

H = 0.1 / 0.03 = 3

Thus, the empirical formula of the compound is CH₃

<h3>2. How to determine the molecular formula</h3>

Empirical formula = CH₃
Molar mass = 30 g/mol
Molecular formula =?

Molecular formula = empirical × n = mass number

[CH₃]n = 30

[12 + (3×1)]n = 30

15n = 30

Divide both side by 15

n = 30 / 15

n = 2

Molecular formula = [CH₃]n

Molecular formula = [CH₃]₂

Molecular formula = C₂H₆

Learn more about empirical formula:

brainly.com/question/24297883

#SPJ1

4 0

2 years ago

1. Butane gas (C4H10) combusts with oxygen gas (O2) to form water (H2O) and carbon dioxide (CO2). Write a balanced;’ equation fo

Mars2501 [29]

Answer:

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.

Explanation:

To balance a chemical reaction, we apply the law of conversation of mass, states that the no. of atoms in both sides of the reactants and products is the same.

So, the balanced equation of combustion of butane is:

<em>It is clear that 2.0 moles of butane is burned in 13.0 moles of oxygen to produce 8.0 moles of CO₂ and 10.0 moles of H₂O.</em>

5 0

3 years ago

How many gallons of a 60% antifreeze solution must be mixed with 70 gallons of 25% antifreeze to get a mixture that is 50% a

Neporo4naja [7]

Answer:

The answer to your question is 175 gallons

Explanation:

Data

60% antifreeze solution volume = ? = x

25% antifreeze solution volume = 25%

Final concentration 50%

Process

0.6x + 0.25(70) = 0.5(70 + x)

Simplification

0.6x + 17.5 = 35 + 0.5x

0.6x - 0.5x = 35 - 17.5

0.1x = 17.5

x = 17.5/0.1

Result

x = 175 gallons

6 0

4 years ago

A flash distillation chamber operating at 101.3 kpa is separating an ethanol water mixture the feed mixture contains z weight et

Alex73 [517]

Answer:

The answer is $[\frac{LX_1}{46} + \frac{L(1-x)}{18}]\times0.454$ mol/hr

$[\frac{Vy_1}{46}+\frac{V(1-y)}{18}]\times0.454$ mol/hr

Explanation:

For flash distillation

F = V+L

$\frac{V}{F} + \frac{L}{F} = 1$

$\frac{F}{V} -\frac{L}{V} = 1$

Fz = Vy+Lx

Y = $\frac{F}{V}\times Z - \frac{L}{V}\times X$ let, $\frac{V}{F} = F$

$y = \frac{Z}{F} -[ \frac{1}{F} -1]\times X$

Highlighted reading

F = 299; $\frac{V}{F}$ = 0.85 ; z = 0.36

y = $\frac{0.36}{0.85} - (-0.15)\times X$

= 0.423 + 0.15x ------------(i)

$y^{*}$ = -43.99713 $x^{6}$ + 148.27274 $x^{5}$ - 195.46 $x^{4}$ +127.99 $x^{3}$ -43.3 $x^{2}$ + 7.469 $x^{}$ + 0.02011

At equilibrium, $y^{*}$ = y

0.423+0.15 $x^{}$ = $y^{*}$

-43.99713 $x^{6}$ + 148.27274 $x^{5}$ - 195.46 $x^{4}$ +127.99 $x^{3}$ -43.3 $x^{2}$ + 7.319 $x^{}$ -0.403

F(x) for Newton's Law

Let $x_{0} = 0$

$x_{1}$ = $\frac{0-[{-0.403}]}{7.319}$

= 0.055

$x_{2}$ = $\frac{{0.055}-{f(0.055)} {{{{{{{}}}}}}}}{f^{'} (0.055)}$

= $\frac{{(0.055)}-(-0.11)}{3.59}$

= 0.085

$x^{3}$ = $\frac{{0.085}-(0.024)}{2.289}$

= 0.095

$x^{4}$ = $\frac{{0.095}-(-0.0353)}{-1.410}$

= 0.07

From This x and y are found from equation (i) and L and V are obtained from $\frac{V}{F}$ and F values

$[\frac{LX_1}{46} + \frac{L(1-x)}{18}]\times0.454$ mol/hr

$[\frac{Vy_1}{46}+\frac{V(1-y)}{18}]\times0.454$ mol/hr

8 0

3 years ago

An empty party balloon will float to the ceiling of a room once it is filled with helium.

lidiya [134]

Helium is a gas composed of itself, were air is composed of Oxygen and Nitrogen making the air more dense than the helium making it float to find other gases

Two factors to change are Air pressure (due to the balloon moving ) and the helium making the balloon rise.

That's about all I can explain...hope this helps >.<

5 0

3 years ago