Answer:
Explanation:
(NH4)3 PO4 +NaOH arrow Na3PO4 +3NH3 +3H2O
Start by seeing what happens with the Na. You need 3 on the left, so put a 3 in front of NaOH
(NH4)3 PO4 +3NaOH arrow Na3PO4 +3NH3 +3H2O Next work with the nitrogens. YOu have 3 on the left and 3 on the right, so they are OK. Next Go to the stray oxygens.
You have 3 on left in (NaOH) and three on the right in 3H2O so they are fine as well. The last thing you should look at are hydrogens.
There are 12 + 3 on the left which is 15. There are 9 (in 3NH3) and 6 more in the water. They seem fine.
Why didn't I do something with the PO4^(-3)? The reason is a deliberately stayed away from them and balanced everything else. Since they were untouched with 1 on the left and 1 on the right, they are balanced.
Species Na H O N PO4
Left 3 15 3 3 1
Right 3 15 3 3 1
Explanation:
It is known that formula for area of a sphere is as follows.
A = 
= 
= 3.14 
= (27 + 273.15) K = 300.15 K
T = (77 + 273.15) K = 350.15 K
Formula to calculate the net charge is as follows.
Q = 
where, e = emissivity = 0.85
s = stefan-boltzmann constant = 
A = surface area
Hence, putting the given values into the above formula as follows.
Q =
= 
= 1046.63 W
Therefore, we can conclude that the net flow of energy transferred to the environment in 1 second is 1046.63 W.
Answer:
Hydrogen is usually classified as a group 1 element since it has one valence electron, just like group 1 metals.
Explanation:
Answer: 1.348 ×10^23 atoms
Explanation:
Given that volume = 1.00L
At standard condition, the volume of a gas is 22.4L/mol (at S.T.P)
Volume = mole /volume at STP
1 = mole/22.4
Mole= 22.4mol.
Also
Mole = number of atoms /Avogradro constant
Where avogrado's constant = 6.02×10²³
22.4 = number of atoms/6.02×10²³
Number of atoms = 1.348×10^25atoms
The reaction of Ca(oH)2 with HCl produces calcium chloride (CaCl2) and water (H2O). The stiochiometric equation is 2HCl + Ca(OH)2 = CaCl2 + 2H2O. In this case, 2 moles of HCl stoichiometrically reacts with one mole of calcium hydroxide. Hence for 3.5 moles of Ca(OH)2, there should be 1.75 moles of HCl needed. Given 0.85 M HCl, to get the volume, we divide 1.75 moles by 0.85 M. The volume needed is 2.0588 liters.
