How much water must be added to 40.0 g of CaCl2 to produce a solution that is 35.0 wt% CaCl2?
1 answer:
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Answer: pH of the solution after the addition of 600.0 ml of LiOH is 7.
Explanation:
The given data is as follows.
Volume of = 900.0 ml = 0.9 L,
Molarity of = 0.18 M,
Hence, we will calculate the number of moles of as follows.
No. of moles = Molarity × Volume
= 0.18 M × 0.9 L
= 0.162 moles
Volume of NaOH = 600.0 ml = 0.6 L
Molarity of NaOH = 0.27 M
No. of moles of NaOH = Molarity × Volume
= 0.27 M × 0.6 L
= 0.162 moles
This shows that the number of moles of is equal to the number of moles of NaOH.
Also we know that,
As 1 mole of reacts with 1 mole of NaOH then all the hydrogen ions and hydroxide ions will be consumed.
This means that pH = 7.
Thus, we can conclude that pH of the solution after the addition of 600.0 ml of LiOH is 7.