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3 years ago

Steve received three payments for a total of $45 how much was each payment

Mathematics

2 answers:

defon3 years ago

5 0

Answer:

$15

Step-by-step explanation:

Assuming all the payments are the same, simply divide the total with the amount of payments:

45/3 = 15

$15 each payment.

kirill115 [55]3 years ago

3 0

Answer:

15 dollars each

Step-by-step explanation:

45/3 = 15

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If the conversion rate for Swiss francs is 1.68 francs = 1 U.S. dollar, then how many Swiss francs can be exchanged for $79.00 i

Likurg_2 [28]

If one U.S. dollar is as much as 1.68 Swiss francs, then 79,00 U.S. dollars will be as much as 79,00 * 1,68, which is 132,72 Swiss francs.

I hope it will help :)

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3 years ago

use the identity below to complete the tasks a^3-b^3=(a-b)(a^2+ab+b^2) when using the identity for the difference of two cubes t

zheka24 [161]

Answer:

see explanation

Step-by-step explanation:

Given that the the difference of cubes is

a³ - b³ = (a - b)(a² + ab + b²)

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64 $x^{6}$ - 27 ← a difference of cubes

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2 years ago

Read 2 more answers

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xxMikexx [17]

Answer:

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Step-by-step explanation:

4 0

3 years ago

A study of pollutants showed that certain industrial emissions should not exceed 2.3 parts per million. You believe a particular

Musya8 [376]

Answer:

$t=\frac{3.3-2.3}{\frac{0.4}{\sqrt{9}}}=7.5$

The degrees of freedom are given by:

$df=n-1=9-1=8$

And the p value would be:

$p_v =P(t_{(8)}>7.5)=0.0000346$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 2.3 ppm the safe limit

Step-by-step explanation:

Information provided

$\bar X=3.3$ represent the sample mean in ppm

$s=0.4$ represent the sample standard deviation

$n=9$ sample size

$\mu_o =2.3$ represent the value to verify

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if the true mean is higher than 2,3 ppm, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2.3$

Alternative hypothesis: $\mu > 2.3$

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{3.3-2.3}{\frac{0.4}{\sqrt{9}}}=7.5$

The degrees of freedom are given by:

$df=n-1=9-1=8$

And the p value would be:

$p_v =P(t_{(8)}>7.5)=0.0000346$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 2.3 ppm the safe limit

6 0

3 years ago

40 is 20 of what number

AleksAgata [21]

$\huge\text{Hey there!}$

$\large\text{40 is 20\% of what time number?}\\\\\\\bullet \large\bold{We\ are\ looking\ for\ your\ UNKNOWN\ number; we\ can\ the\ value}\\\large\bold{is\ \underline{a}\ for\ our\ answer!}\\\bullet\large\bold{REMEMBER: Percentages\ are\ out\ 100\ \& the\ word\ \underline{of}\ means\ \underline{multiply}}$

$\huge\text{NOW LETS SOLVE FOR YOUR ANSWER!}$

$\bold{Equation: 20\%\ \times \ a\ =\ 40}\\\\\bold{a = \dfrac{40}{20\%}}}\\\\\bold{20\% = \dfrac{20}{100}\rightarrow 0.2}}}\\\\\bold{Equation: a = \dfrac{40}{0.2}}\\\\\bold{\dfrac{40}{0.2}=200}\\\\\bold{a=200}\\\\\boxed{\boxed{\bold{Answer: 200}}}\huge\checkmark$

$\large\textsf{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

7 0

2 years ago

Steve received three payments for a total of $45 how much was each payment￼￼￼

Steve received three payments for a total of $45 how much was each payment