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son4ous [18]
4 years ago
10

The both that are not in green I don't know how to do them . I need some help.

Mathematics
1 answer:
attashe74 [19]4 years ago
3 0

Answer:

Step-by-step explanation:

B. 0.00604

D.1.47 ×10^{-3}

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Cylinder A has a radius of 10 inches and a height of 5 inches. Cylinder B has a volume of 750π. What is the percentage change in
Firlakuza [10]

Answer:

50% change in volume

Step-by-step explanation:

<h2>This problem bothers on the mensuration of solid shapes.</h2>

In this problem we are to find the volume of the first  cylinder and compare with the second cylinder.

Given data

Volume v =  ?

Diameter d= ?

Radius r =  10 in

Height h=  5 in

we know that the volume of a cylinder is expressed as

volume = \pi r^{2}h

Substituting our given data we have

volume = \pi*10^{2}*5\\ volume= \pi *100*5\\volume= 500\pi in^{3} \\

The first cylinder as a volume of 500\pi

The change in volume is 750\pi - 500\pi = 250\pi

percentage = \frac{250\pi }{500\pi } *100

percentage=0.5*100= 50%

6 0
3 years ago
Read 2 more answers
What's the input lol *photo attatched*​
marishachu [46]
-20+1= -19
-19/2= -9.5

Check:
-9.5x2= -19
-19-1= -20
3 0
2 years ago
Jose is going to watch a movie in his collection. He has 7 action movies, 12 comedies, and 2 dramas.
Arte-miy333 [17]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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Please help this is important<br> -1.5x+12=2.5x-12
Anna35 [415]

Answer:

x = 6

Step-by-step explanation:

move all terms to the left:

-1.5x+12-(2.5x-12)=0

get rid of parentheses

-1.5x-2.5x+12+12=0

add all the numbers together, and all the variable.

-4x+24=0

move all terms containing x to the left, all other terms to the right

-4x=-24

x=-24/-4 - divide

x=+6

7 0
3 years ago
What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
8 0
3 years ago
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