Since 111 is greater than 33, I will assume that you meant 11 votes for a candidate. Also, assuming that each student can vote only once, the answer would be
11/33 x 100=33.333333...
About 33.333 of the voters voted for candidate a.
Answer:
Step-by-step explanation:
Let <em>A</em> be the event of getting an odd number.
<em>P(A)</em> be the probability of getting an odd number.
Total odd numbers here are 6 i.e. 
Here, total numbers in the game are 12 i.e 
.
Formula for probability of an <em>event E</em> can be observed as:
Let <em>B</em> be the event of getting 11.
<em>P(B)</em> be the probability of getting 11.
Total number of possible cases is 1.
is the probability that we get 11 and an odd number.
Possible number of cases = 1
<em>P(B/A)</em> is the probability that we get an 11 given that it is an odd number.
Hence, P(B/A) =
Answer:
B. x =1 , y = -5
Step-by-step explanation:
So, what we can do is to simply plug in all of the equations and see which one fits. Equation: x - y = 6
A. x =1 , y = -6
1 -(-6) = 6
1 + 6 = 7
A would be incorrect.
B. x = 1, y = -5
1 - (-5) = 6
1 + 5 = 6
Therefore, B would be correct.
Answer: √
145 or 12.04159457 for the decimal ways try 12
Step-by-step explanation: 12.0415945787923
Midpoint (−2,−9.5)
Slope −0.0833333333333333
x intercept −116.00
y intercept −9.67
Answer:
You add all them then divided 4 i think
