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Korolek [52]
3 years ago
9

​(A) How many ways can a 3​-person subcommittee be selected from a committee of 6 ​people? ​(B) How many ways can a president co

mma vice dash president comma and secretary be chosen from a committee of 6 ​people?
Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

A) N = 20 ways

a 3​-person subcommittee can be selected from a committee of 6 ​people in 20 ways.

B)N = 120 ways

The president, vice president and secretary can be chosen from a committee of 6 ​people in 120 ways.

Step-by-step explanation:

A) the number of ways a 3​-person subcommittee be selected from a committee of 6 ​people N;

Since there is no given order for the selection, this means that the order of selection is irrelevant. Therefore, this is a combination problem where order is not considered.

N = nCr

N = 6C3

N = 6!/3!(6-3)! = 6!/3!3!

N = 720/(6×6)

N = 20 ways

a 3​-person subcommittee can be selected from a committee of 6 ​people in 20 ways.

B) the number of ways a president, vice president and secretary can be chosen from a committee of 6 ​people N;

In this case, there is a given order of selection for the 3 posts. This is a permutation.

N = nPr

N = 6P3

N = 6!/(6-3)!

N = 6!/3!

N = 120 ways

The president, vice president and secretary can be chosen from a committee of 6 ​people in 120 ways.

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2 years ago
What is each power of i with its multiplicative inverse.
pentagon [3]

Answer:

1) multiplicative inverse of i = -i

2) Multiplicative inverse of i^2 = -1

3) Multiplicative inverse of i^3 = i

4) Multiplicative inverse of i^4 = 1

Step-by-step explanation:

We have to find multiplicative inverse of each of the following.

1) i

The multiplicative inverse is 1/i

if i is in the denominator we find their conjugate

=1/i * i/i\\=i/i^2\\=We\,\, know\,\, that\,\, i^2 = -1\\=i/(-1)\\= -i

So, multiplicative inverse of i = -i

2) i^2

The multiplicative inverse is 1/i^2

We know that i^2 = -1

1/-1 = -1

so, Multiplicative inverse of i^2 = -1

3) i^3

The multiplicative inverse is 1/i^3

We know that i^2 = -1

and i^3 = i.i^2

1/i^3\\=1/i.i^2 \\=1/i(-1)\\=-1/i * i/i\\=-i/i^2\\= -i/-1\\= i

so, Multiplicative inverse of i^3 = i

4) i^4

The multiplicative inverse is 1/i^4

We know that i^2 = -1

and i^4 = i^2.i^2

=1/i^2.i^2\\=1/(-1)(-1)\\=1/1\\=1

so, Multiplicative inverse of i^4 = 1

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Answer:

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Step-by-step explanation:

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False.

Step-by-step explanation:

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