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Korolek [52]
3 years ago
9

​(A) How many ways can a 3​-person subcommittee be selected from a committee of 6 ​people? ​(B) How many ways can a president co

mma vice dash president comma and secretary be chosen from a committee of 6 ​people?
Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

A) N = 20 ways

a 3​-person subcommittee can be selected from a committee of 6 ​people in 20 ways.

B)N = 120 ways

The president, vice president and secretary can be chosen from a committee of 6 ​people in 120 ways.

Step-by-step explanation:

A) the number of ways a 3​-person subcommittee be selected from a committee of 6 ​people N;

Since there is no given order for the selection, this means that the order of selection is irrelevant. Therefore, this is a combination problem where order is not considered.

N = nCr

N = 6C3

N = 6!/3!(6-3)! = 6!/3!3!

N = 720/(6×6)

N = 20 ways

a 3​-person subcommittee can be selected from a committee of 6 ​people in 20 ways.

B) the number of ways a president, vice president and secretary can be chosen from a committee of 6 ​people N;

In this case, there is a given order of selection for the 3 posts. This is a permutation.

N = nPr

N = 6P3

N = 6!/(6-3)!

N = 6!/3!

N = 120 ways

The president, vice president and secretary can be chosen from a committee of 6 ​people in 120 ways.

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4 years ago
Which equation, when solved, results in a different value of x than the other three?
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I would have to say -7(1/8)x-4/3=20.


The first and the second one both result in
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3 years ago
A recipe calls for 4c of flour. You have 20 c of flour. Let r represent the flour you when left after making the recipe. Is the
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3 years ago
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ioda

Answer:

see explanation

Step-by-step explanation:

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3 years ago
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