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klasskru [66]
3 years ago
15

A hardware store offers customers a coupon for `\$25` off. The regular price of a power drill is `\$125`. If a customer uses the

coupon, what percent will the customer save?
Mathematics
1 answer:
Goryan [66]3 years ago
8 0

Based on the information given, the percentage that will be saved by a customer that uses coupon will be 20%.

  • Amount on coupon off = $25
  • Regular price of power drill = $125

The amount that a customer that uses the coupon will pay = $125 - $25 = $100

Therefore, the percentage that is saved will be:

= 25/125 × 100

= 1/5 × 100

= 20%

In conclusion, the correct option is 20%.

Learn more about percentage on:

brainly.com/question/25820076

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grigory [225]
First, Rico walked for 3/10 of a mile which is 30/100 of a mile.
Hen, Rico walked for 24/100 of a mile.
Then you add 24/100 and 30/100. 24+30/100 which is 54/100.
Answer=54/100 of a mile
4 0
4 years ago
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2(x+1)=38 I would just like to check my answer for this problem. I think x equals 16. But I would like to clarify
astraxan [27]

There are two methods to do this:

1. 2(x + 1) = 38

2*x + 2*1 = 38 (Expand the bracket)

2x + 2 = 38

2x = 36 (Subtract 2 from both sides)

x = 18 (Divide each side by 2)

2. 2(x + 1) = 38

(x + 1) = 19 (Divide each side by 2)

x = 18 (Subtract 1 from each side)

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4 years ago
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How do i solve this step by step??
Levart [38]

Answer:

x = 30

Step-by-step explanation:

well the two agnles are congruent so they have to equal the same angle

x+ 90 = 4x

solve for x bye subtracting x from 90

90 = 3x slove by dividing 90 by 3 getting x alone

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3 0
3 years ago
Rewrite the function by completing the square. 4x^2-4x+1=0
andrey2020 [161]

Do in <u>completing the square method.</u>

{4x}^{2}  - 4x + 1 = 0 \\ 4x^{2}-4x=-1  \\ \frac{4x^{2}-4x}{4}=\frac{-1}{4}  \\ x^{2}+\frac{-4}{4}x=\frac{-1}{4}  \\ x^{2}-x=\frac{-1}{4}  \\ x^{2}-x+\left(-\frac{1}{2}\right)^{2}=-\frac{1}{4}+\left(-\frac{1}{2}\right)^{2}  \\ x^{2}-x+\frac{1}{4}=\frac{-1+1}{4}  \\ x^{2}-x+\frac{1}{4}=0  \\ \left(x-\frac{1}{2}\right)^{2}=0  \\ \sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{0}

Now simplify.

x-\frac{1}{2}=0 \\  x-\frac{1}{2}=0  \\  \\  \rightarrow \: x=\frac{1}{2}  \\  \rightarrow \: x=\frac{1}{2}

So, answer is..

\boxed{x=\frac{1}{2} }

Now <u>rewrite</u> the equation.

4 x ^ { 2 } - 4 x + 1 = 0 \\  \boxed{4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0  }

<u>Verification :-</u>

4 x ^ { 2 } - 4 x + 1 = 0 \\ 4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0  \\ 1-4\times \left(\frac{1}{2}\right)+1=0  \\ 1-\frac{4}{2}+1=0  \\ 1-2+1=0  \\ -1+1=0  \\ \underline{ 0 = 0} \:  \\  \dashrightarrow \text{true}

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Which expression has a positive value?
e-lub [12.9K]
3(-64/8)+25 will give you a positive value of 1
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3 years ago
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