Answer:
1st problem: b) 
2nd problem: c) 
Step-by-step explanation:
1st problem:
The formula/equation you want to use is:
where
t=number of years
A=amount he will owe in t years
P=principal (initial amount)
r=rate
n=number of times the interest is compounded per year t.
We are given:
P=2500
r=12%=.12
n=12 (since there are 12 months in a year and the interest is being compounded per month)
Time to clean up the inside of the ( ).
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2nd Problem:
Compounded continuously problems use base as e.
P is still the principal
r is still the rate
t is still the number of years
A is still the amount.
You are given:
P=2500
r=12%=.12
Let's plug that information in:
.
Answer:
A. <em>A </em>and <em>F</em>.
Step-by-step explanation:
By observing the number line given, you can assume that in between -4 and -6 would be the number -5, replaced by the variable <em>A</em>, and the same thing with 4 and 6, where 5 is replaced by <em>F</em>.
Answer:
The equation in the standard form of the line through the given points is;
y = 3x - 17
Step-by-step explanation:
We start by getting the slope of the line;
m = (y2-y1)/(x2-x1)
m = (7-10)/(8-9) = -3/-1 = 3
The stands equation form is;
y = mx + b
m is slope, b is the y-intercept
so we have
y = 3x + b
To get b, we substitute the coordinates of any of the points
10 = 3(9) + b
10 = 27 + b
b = 10-27
b = -17
So the equation is;
y = 3x - 17
It’s square of pie because the lines don’t match up to you
