When you see questions of this nature, test the individual inequalities and look out for their intersection.
For

Choose a point in the lower or upper half plane created by the line

The above line is the one which goes through the origin.
Now testing (1,0) yields,

That is,

This statement is true. So we shade the lower half of

For

We test for the origin because, it is not passing through the origin.

This yields

This statement is false so we shade the upper half.
The intersection is the region shaded in B. The top right graph
Answer:
negative number
Step-by-step explanation:
Numerator is 125 as dividing makes 875/1000
Numerator is 0.875 we can divide again by 8.75/10
we find that 0.875 = 875/1000 is equivalent to 7/8
Answer:
DDDDD...............................
Permutation: In a race of 10 students, find the number of ways students can finish 1st, 2nd, and 3rd. In this case the order matters, so it is a permutation.
10 x 9 x 8 = 720 ways
Combination: In a class of 10 students, find the number of ways a group of 3 students can be selected to win a prize. In this case the order doesn't matter, so it's a combination.
10 x 9 x 8 / (3 x 2 x 1) = 120 ways
I believe that answer is B. (The second one)
Hope this helped !!