ZEROS: -4,6,10 are the answers to x
3x - 5 + 2x = 15+ 4x - 5
5x - 5 = 10 + 4x
5x - 5 + 5 = 10 +5 +4x
5x = 4X + 15
5x - 4x = 4x - 4x + 15
x = 15
Are you sure it’s a scalene triangle because if you only know one side and all the other sides are different lengths then it’s impossible to computer unless we know angle measures. It would have to be isoceles or we would need angle measures
Answer:
The coordinates of the other end is 
Step-by-step explanation:
Given


Required
Find the coordinates of the other end
Let Midpoint be represented by (x,y);
(x,y) = (5,2) is calculated as thus

So
and 
Where
and 
So, we're solving for 
Solving for 
Substitute 5 for x and -6 for x₁

Multiply both sides by 2


Add 6 to both sides


Solving for 

Substitute 2 for y and 2 for y₁

Multiply both sides by 2


Subtract 2 from both sides



Hence, the coordinates of the other end is 